Getting linker error when trying to build a native library for Android x64 or x86 arch using library mode. ld: error: relocation R_X86_64_PC32 cannot be used against symbol fmodf; recompile with -fPIC >>> defined in /Users/sergey.fedotov/Library/Android/sdk/ndk/23.2.8568313/toolchains/ll...
ld: error: relocation R_X86_64_32S cannot be used against local symbol; recompile with -fPIC >>> defined in htslib/bcf_sr_sort.o >>> referenced by bcf_sr_sort.c >>> htslib/bcf_sr_sort.o:(bcf_sr_sort_next) ld: error: relocation R_X86_64_32S cannot be used against local symbo...
Other symbol errors on Android are likely to be due to previously mention reasons; e.g., missing or incorrect dependencies, incorrect package names, method or fields that don't exist in a particular API version, spelling / typing errors, and so on. Hiding system classes: I've s...
Finally, evaluate each Project by executing its build.gradle file, if present, against the project. (source) This means that in your kotlin build scripts, the receiver type (i.e. this) is KotlinBuildScript which is eventually a subclass of Project. I don't know the details about how it'...
binary, I found that inline functions (from stdio.h) were failing but regular functions (in libc.so) worked. I also found that the busybox binary had the symbol "__sF" and so did libc.so. Normally, the binary would have an undefined reference that would be satisfied at runtime ...
Used Japanese locale once, yen symbol persists in filepath User Administrator account UI performance slow user created schedule tasks disappearing user folder name does not match my microsoft account name User policy could not be updated successfully. User profile migration - Copy local user account ...
binary, I found that inline functions (from stdio.h) were failing but regular functions (in libc.so) worked. I also found that the busybox binary had the symbol "__sF" and so did libc.so. Normally, the binary would have an undefined reference that would be satisfied at runtime ...
The mental disconnect I think you (and tbf many many other people) have here is that the strength of the password is different than the strength of the rule used to generate it. You are assuming that because the rule you use to generate the password could only be...
{\boldsymbol{R}}}\,{{\exp }}\left[-U\left({N}_{{{\rm{He}}}\,-\,1,{N}_{{{\rm{X}}}\,+\,1\right)/{k}_{B}T\right]}{{\int }_{V}d{{{\boldsymbol{R}}}\,{{\exp }}\left[-U\left({N}_{{{\rm{He}}},{N}_{{{\rm{X}}}\right)/{k}_{B}T\right]}\rig...
Leaving Everyone or other far-reaching security principals in place here would be irresponsible and may cause earn you the ire of policy administrators, so don't abuse the trust here: On the Conditions page, choose Path (we're going to take the easy optio...