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Implicit differentiation is used when a function is defined implicitly rather than explicitly. It allows you to find derivatives without solving for one variable in terms of others, which is particularly useful for equations where the dependent variable is intertwined with the independent variable. Comp...
(isolate y for later not necessary) lny = 2 - x² - 2lnx y = e^(2 - x² - 2lnx) Implicitly differentiate. 2/x + y'/y = 0 - 2x y'/y = -2x - 2/x y' = y(-2x-2/x) Solve @ x=1 y'= e^(2-1-2ln1) * (-2-2) y' = e*-4 y' = -4e Upvote • 1 Do...
Steps for using the Chain Rule Step 1: Identify the external function f(x) and the internal function g(x) Step 2: Make sure that f(x) and g(x) are valid, differentiable functions, and compute the corresponding derivatives f'(x) and g'(x) Step 3: Use the formula (f \circ g)...
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