Calculate (a) the work done by the 40-N force, (b) the work done by gravity, (c) the work done by friction, and (d) the change in kinetic energy of the block. Homework Equations The Potential and Kinetic Energy equations The Attempt at a Solution I managed to get all the parts...
Homework Statement There's a mass (16.6 kg) on a surface with kinetic coeficient of friction 0.181. it's being pulled by a constant force of 161 N at 26...
The friction work is calculated with considering the potential change of contact surfaces during sliding. The potential change can be gained by a universal adhesive energy function. The relationships between frictional force and parameters of a tribo-system, such as surface energy and microstructure of...
The amount of work done upon an object depends upon the amount of force (F) causing the work, the displacement (d) experienced by the object during the work, and the angle (theta) between the force and the displacement vectors. The equation for work is .
and the AB=S1 is Ep= When the wood block starts from the B point and is stopped by the projectile and moves to the C point to stop, during the whole process, the sliding friction force should be overcome to do the work, and the elastic potential energy is converted into internal energ...
force equilibrium and thermal fluctuations). In the absence of force and in a dilute solution, the average lifetime of a protein–protein interaction bond is the inverse of its unbinding constant,[Math Processing Error]⟨τoff⟩=1/koff. We consider an ensemble with[Math Processing Error]N...
Friction force and torque models under nonuniform assumption are derived. Comparisons of the determined friction force and torque with the results from uniform assumption are made. In addition, the differences between constant friction coefficient and varying coefficient are revealed. Moreover, two ...
The pressure drop occurring across the microtube is mainly composed of three parts: (1) Pressure loss along the flow path due to fluid wall friction; (2) pressure loss due to the sudden change in the pipe diameter; (3) pressure difference across the fluid interface due to capillary pressure...
How much work is done on the body by the applied force F with arrow between t = 0 and t = 0.5 s? Homework Equations x=vot +1/2at^2 v=at m/2(Vf^2-Vi^2) The Attempt at a Solution When I work the problem I get 0.152 Joules. .8 = 1/2 a(2.0)^2 a=0.4 v=0.4(0.5) ...
Homework Statement A man is pulling a 40.0 kg crate across a level floor with a horizontal force, and the coefficient of kinetic friction is μk = 0.59...