Example 5:What is the lowest circuit conductors’ ampacity allowed for a feeder supplying one 208-V, 3-phase, 3-hp motor and one 208-V, single-phase, 2-hp motor? Solution: Step 1:From Table 430.250 FLC 3-hp motor = 10.6 A From table 430.248 FLC 2-hp motor = 13.2 A Step 2:High...
Motor current / Torque Motor full load current = (Kw x 1000) / (1.732 x Volt (L-L) x P.F Motor full load current= 300 × 1000 / 1.732 x 460 x 0.8 = 471 Amp. Motor locked rotor current = Multiplier x Motor full load current Locked rotor current (Kva/Hp) Min. motor ...
At each data point in an in-use test, engine speed and engine torque are read from the engine's electronic control unit, and along with time, are used to determine instantaneous engine power. Instantaneous work is calculated using this power and the time differential in the data collection. ...
Each spring 619A is of sufficient strength to overcome the opposing torque on shaft 618 which is exerted by spring 623 (Figure 7), therefore the plate 620 is brought to the highest of these three levels if the subtotal register wheel 401 registers more than the grand total register wheel ...
Instability in the head from the turbine or in the flow rate processed; - Cavitation due to the presence of low suction pressures; - Water hammer, which stresses both the piping system and the mechanical parts of the PAT. There are therefore strong fluctuations in the torque that is transmitt...
Instability in the head from the turbine or in the flow rate processed; - Cavitation due to the presence of low suction pressures; - Water hammer, which stresses both the piping system and the mechanical parts of the PAT. There are therefore strong fluctuations in the torque that is transmitt...