Mole is an important concept used in chemistry. It represents the amount of molecule which has the exact mass of its gram molecular mass. One mole also contains an Avogadros number of molecules.Answer and Explanation: The number of moles can be calculated using following formulas- Using ...
Calculating the Number of Moles in a Solution 4 Finding the Boiling Point of a Liquid 本學習集中的詞語(6) Converting from Moles to Mass Multiply by Molar Mass (g) / 1 Mole Converting from Mass (g) to Moles 1 Mole x/ Molar Mass (g) ...
use the ideal gas constant to calculate the number of moles of water vapor. p=18.65 torr v=39.5 L r=0.08206 t=294 K this is the equation im supposed to use right? n= PV/RT This is what i got. n=(18.65)(39.5)/(0.08206)(294)=30.5 mol H20 but when i look it up online the ...
Molalityis the number of moles of solute per kilogram of solvent. Because the density of water at 25°C is about 1 kilogram per liter, molality is approximately equal to molarity for dilute aqueous solutions at this temperature. This is a useful approximation, but remember that it is only an...
Concentration in moles/liter (C) = (dilution factor × A260) ÷ (sum of extinction coefficient contributions × cuvette path length) For our example, that would be: C = (100 x 0.135) ÷ (257,300 x 0.4) C = 13.5 ÷ 102,920 C = 0.0001...
Molarity = MolesofsoluteLitresofsolutionWith the help of the above formula, if we know the molarity (concentration) of a solution and the total volume of the solution in litres, we can determine the number of moles of solute. Then the mole of solute is converted to grams....
Calculate the amount of acid to use in each titration. Assume thaqt you are using 0.512 M Na OH (aq). A good volume of NaOH to use per titration is 15 mL. From this molarity and volume, the moles of N Explain what is meant by t...
A 1 molar (M) solution contains 1 mole of solute in 1 liter of solution. A 1 micromolar (µM) solution contains 1 µmol of solute in 1 liter of solution. This is equivalent to 0.000001 (1 x 10^-6) moles per liter. A 1 picomolar ...