百度试题 题目 Calculate the base current for this voltage-divider bias circuit.( ) 相关知识点: 试题来源: 解析 596.55 μA 反馈 收藏
Calculate the base current for this voltage-divider bias circuit.( ) A. 233.78 μA B. 34.62 μA C. 596.55 μA D. 76.8 μA 如何将EXCEL生成题库手机刷题 如何制作自己的在线小题库 > 手机使用 分享 反馈 收藏 举报 参考答案: C 复制 纠错 举一反三 下列情况适合用汗法的是 A. ...
The current divider formula is applicable in situations where there is a parallel network of various elements. Also, the current divider rule formula can help you determine the current in every branch of a circuit. The main use of the current divider is to help generate a proportion of the a...
Calculate the quiescent drain current and the gate-to-source voltage for this voltage-divider bias circuit. 点击查看答案 你可能感兴趣的试题 团中央、全国少工委要求地方团队组织重点推动开展哪四个方面的爱国主义教育活动? 点击查看答案 单项选择题精细合成单元反应课程主要介绍有机合成反应机理及各种单元操作,如...
Calculate the drain-gate voltage for this voltage-divider bias circuit. A、VDG = 8.42 V B、VDG = 7.42 V C、VDG = 6.42 V D、VDG = 5.42 V 点击查看答案 第2题 Calculate the quiescent drain current and the gate-to-source voltage for this voltage-divider bias circuit. A、IDQ = 2.4...
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Calculating Current Limiter Resistor The value of this resistor may be calculated through the below given formula: R = (supply voltage VS – LED forward voltage VF) / LED current I Here R is the resistor in question in Ohms Vs is the supply voltgae input to the LED ...
When calculating thepower dissipationof resistive components, we can use any one of the threeOhm’s lawpower equations if given any two of thevoltage (V), current (I), andresistance (R): P=IV=I2R=V2RP=IV=I2R=V2R Calculating Power Using the Table Method ...
R1 will have 5V minus 2.2V, giving us 2.8V across it. Instead of calculating current, we can look at the ratio (because we can do that in our head). If 2V is equal to 50kΩ, then 2.8V is equal to 70kΩ (1.4 times 50kΩ). ...
Then, the current in the circuit is done by the device in series with the signal generator. For circuits with high input impedance the current is very small and difficult to measure.R = U / I. Therefore, we choose for the measurement of high-impedance circuits, a better method. It puts...