Cau 3: Thuc hien cac phep tinh sau.a(x^2-2)/(x-1)-(-1)/(x-1) (x+3)/(x^2-4)-1/(x^2-4) c)(x-2)/(x-6)-(18-x)/(x-6)+(x+2)/(x-6) d)(5x^2+x+4)/(x^3-8)-(x^2-2x)/(x^3-8)-(x^2-3x-8)/(x^3-8) ...
Cau 3. Thuc hien cac phep tinh sau: a.(1-6x)/(6x-1)+(2x-2)/(6x-1)+(4x+1)/(6x-1) b.(x+3)/(x^2-1)-(x+1)/(x^2-x) 相关知识点: 试题来源: 解析 Câu 3.a. (1-6x)/(6x-1)+(2x-2)/(6x-1)+(4x+1)/(6x-1)-(10)/6-=-11+1∴ 反馈 收藏 ...
1 A. Thuc hien cac phep tinh sau:A=((x^2+3x)/(x^2-9)+(3x)/(x^2-6x+9))⋅(1-2/x-3/(x^2)) x2+3x3x a) A =+x2-9x2-6x+9vó i x∈ {0;3};b)B=(4/(x(x^2-4))+(x-2)/(x^2-4):((x-2)/(x(x+2))-x/(2x+4))vói x∈ {0;±2}. ...
百度试题 结果1 题目Bai I: Thuc hien cac phep tinh sau:(-1)/(2-3x)+5/(3x-2)(-x^2)/(2(x+1))+3/(1-x^2)+1/(2(x-1)) 相关知识点: 试题来源: 解析 Mỗi phần 1 điểmKQ a)b) 反馈 收藏
Bai 1: Thuc hien cac phep tinh sau:a)√(27)-√(1/3)-1/(2-√3) b)√(9/(4-2√3))-√((25)/(4+2
Cau 1: Choday⋅Su_t=a√n+b(a,t la cac tham so thuc). Biet H_1+u_9=10 , tinh u. A A. u_4=5 . B. u_4=4 . C.u_4=8 . D. u_s=10 相关知识点: 试题来源: 解析 ATa có: u_1+u_9=(a+b)+(3a+b)=4a+2b=2(2a+b)=() Từ đây ta suy ra...
Cau I: Cho day so u=an+b( a, b la cac tham so thuc). Biet u_1+u_4=10 , tinh u A(1.14)=5 B. u_4=4 . C. u_4=8 . D u_5=10 . 相关知识点: 试题来源: 解析 ATa có: u_1+u_9=(a+b)+(3a+b)=4a+2b=2(2a+b)=()Từ đây ta suy ra u_4=...