Balance C3H4O2 + Cl2 = C3H3ClO2 + HCl Using the Algebraic Method Step 1: Label Each Compound With a Variable Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a C3H4O2 + b Cl2 = c C3H3ClO2 + d HCl Step 2: Create ...
5.实验测得.某有机物相对分子质量为72.(1)若该有机物是烃.其分子式为C5H12.它有3 种同分异构体.若该烃与Cl2发生取代反应.生成的一氯代物只有1种.则该烃的结构简式为C若该有机物3.6g完全燃烧生成0.15molCO2和0.1molH2O.则该有机物的分子式为C3H4O2.若它是一种不饱和羧酸.