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C3240-10-I-PU(Optical Business|Optical Access Network|Industry Sensing|C Series SDC|C3240-10-I-PU) Document List Support Optical Business Optical Access Network Industry Sensing C Series SDC C3240-10-I-PU My Support | Feedback | Help ...
两个正弦交流电解析式分别是i1(t)=10sin(ω1t-30°)A, i2(t)=10sin(ω2t 30°)A,则这两个正弦交流电流之间的相位关系是()。A.反相B.正交C.同相D.无法确定搜索 题目 两个正弦交流电解析式分别是i1(t)=10sin(ω1t-30°)A, i2(t)=10sin(ω2t 30°)A,则这两个正弦交流电流之间的相位关...
【答案】打折后,买40件A商品和40件B商品用了3240元,比不打折少花360元 【解析】 设A商品打折前的单价为x元/件,B商品打折前的单价为y元/件,再根据买20件A商品和30件B商品要用2200元,买50件A商品和10件B商品要用2900列方程组求解. 设A商品打折前的单价为x元/件,B商品打折前的单价为y元/件, 根据题...
下列代码得到1至100之间的一个随机整数(包括1和100)。A.(int)Math.random()*100B.(int)(Math.random()*10)+1C.(i
1.I’m going from New York to California ___(经由)the Panama Canal. 2.My camera can be ___(调整)to take pictures in cloudy and sunny conditions. 3.Both men were ___(困在)inside the burning car in the traffic accident yesterday evening. 4.In order to ___(平衡)the foreign ...
10.His uncle often___(buy)som e delicious food for him and he often___ ___(take)it to the school to eat.11.Lucy and Lily___(go)to sc hool at 7o’clock.Jim___ (go) at 6:45.12.I___ (teach) math here.My father___ (teach) English.13.-- ___Mary often___(watch)-...
现在有10万元,希望5年后达到15万元,求折现率是多少?( ) A. 8% B. 8.14% C. 7.99% D. 8.45% E. P=F(1+i)-n 100000=150000(1+i )-5 F. (1+i )-5 =0.667 内插法求得:i =8.45% 相关知识点: 试题来源: 解析 D.8.45% 反馈 收藏 ...
C3240-10-I-PU İndirilebilir Ürün Dokümantasyonu Paketi(2) Quick Guide to HoloSens SDC Target Capture Camera Site Survey and Commissioning 2022-10-31 Huawei C Series SDC 8.0.2 Product Documentation 2024-07-31 Upgrade Guide(1) Upgrade Paths for Camera Transfer-to-Maintenance Versions...
两个电阻并联,R1=10Ω R2=30Ω,电流I2=3A,则总电流I=(_)A。A.A4B.B6C.C9D.D12搜索 题目 两个电阻并联,R1=10Ω R2=30Ω,电流I2=3A,则总电流I=(_)A。 A.A4B.B6C.C9D.D12 答案 D 解析收藏 反馈 分享