C3H6 + H2SO4 + KMnO4 = C3H4O4 + MnO4S + K2O4S + H2O BrCl + NaOH = NaCl + BrHO Li2O + MgSO4 = Li2O4S + MgO Recently Balanced EquationsBalance C2H4O2 + C2H5NH2 = CH3CONH2 + CH3OCH3 Using the Algebraic Method To balance the equation C2H4O2 + C2H5NH2 = CH3CONH2...
[解答]解:A、H2SO4中含有三种元素,不属于氧化物,故A错; B、CO(NH2)2中含有氮元素,属于氮肥,故B错; C、空气中含有氮气、氧气、二氧化碳等物质,属于混合物,钢铁中含有铁和碳等物质,属于混合物,故C错; D、C2H5OH、CH3COOH中都含有碳元素,都属于有机物,故D正确。 故选:D。 [分析]A、根据氧化物的特点...
You can also ask for help determining oxidation numbers in our chat or forums. 例子 (Al2)((SO4)3) Si2Cl2 (NH3)2(H2SO4) B2Cl4 Be (Zn)Br2 CH(CH) CH3CONO2 Fe((OH)3) C2HBr3 C3H5ON HCOONH3CH3 Recent Oxidation Numbers计算器 化学方程式 化学方程式配平 化学计量计算器 限制试剂计算器...
,反应的方程式为CH-|||-CH3+2CH3Cl催化剂CH-|||-CH3-|||-CH-|||-CH3+2HCl;(6)1molM可与4molNaHCO3反应生成4 mol CO2,则M中含有4mol羧基,则M的结构简式为HOOC-|||-COOH-|||-HOOC-|||-COOH;(7)I为H2N-|||-NH2-|||-COOC2H5、N为HOOC-|||-COOH-|||-HOOC-|||-COOH,氨基与羧基发...
COOH 2SO4Br Br Br CN COOH (8) NH2 CH3 ②KCN CuCN + 出0 CH3 ①NaNO2HCl [O] △ COOH 混酸 (1) NO2 NH2 ___ N(CH3)2 n2ci NaNO2,HCI 弱酸性 N = N N(CH3)2 NH2 弱酸性 NH2 NH2 ch3 ⑶H2SO4 CH3 Na?SO3 CH3 ⑷ 混酸Fe,HCl ,,1,II I H2SO4Na2SO3①NaOH,熔融 混酸一Fe,HC...
h2so:c2h5ohClClCl⑵CH3___CH3NH2b「2CH3FeBrBrNH2BrNO2⑶___HNO3N02___NH2NH2NaNO2h2so4cnnhcoch⑷NH2CH3(5)CH3混酸Fe,HCIchnh(CH3CO)2O混酸nh2nhcochno2(CH3CO)2o hnono2nhcoch3+___1NaNO2,H2S042__C2H5OH__*ch31NO21NaNO2,H2SO2c2h5ohBrno2no2ò3一0òò3H3C_2H_5OHBrBrCNNaNO ...
百度试题 题目 1,3,5-三漠苯 NaClO, NaOH // \___rwi H2SO4 NaNO9 h2so4 nh2 C2H5OH CuSO4 相关知识点: 试题来源: 解析 hnc>3. 反馈 收藏
N-CH2CH2-C c2h5 O cch3 COC2H5 O H+OC2H50 H3ONaBH4 -N-CH2CH2-CH牙CCH3 △C2H5 C2H5?H Ch/n-CH2CH2-CH厂CCH3 ___c2H5—C2HK Br N-CH2CH2-CH厂CCH3 CH3O nh2no2 Snh2 甘油/H2SO4 no2 CH3 匚-NO2 h^chch2ch2ch2n CH3 相关知识点: 试题来源: 解析 HBr 二 反馈 收藏 ...
百度试题 结果1 题目 c2h5oh Cl Cl Cl FeBr Br CH3 Br NH2 1NaNO2,H2SO 2H2O,△ (CH3CO)2O (6) NH2 (CH3CO)20混酸 NO2 NHCOC H Fe ___ H2SO4 ,HCl NH 相关知识点: 试题来源: 解析 NaNO 2 反馈 收藏
【题目】盐酸多利卡因是一种局麻药及抗心律失常药,可由芳香烃A为起始原料合成:A浓HNO3Fe,HCINH2CICH2COCI(CBH1)浓H2SO4/△③①D(C2H5)2NHHCI④⑤F(盐酸利多卡因)NH2已知:NO2 Fe, HCl△回答下列问题:1.B的官能团名称为{{1}}D的分子式为{{2}}。2.反应①的化学方程式为{{1}},反应类型为{{2}...