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解答:解:盐酸酸化的MgSO4溶液存在H+、Mg2+和SO42-离子,加入Ba(OH)2溶液,首先发生Ba2++SO42-=BaSO4↓、H++OH-=H2O,然后发生Mg2++2OH-=Mg(OH)2↓,则一开始就应有沉淀生成,由于盐酸的两不确定,而曲线的变化特点不确定,但可以肯定的是D一定错误,因开始没有沉淀生成,不符合反应实际. ...