count[i]+= count[i -1]; }//将元素移动到有序序列中的正确位置上int*sorted = (int*)malloc(len*sizeof(int));for(i = len -1; i >=0; i--) { sorted[count[arr[i]- min] -1] =arr[i]; count[arr[i]- min]--; }//将有序序列复制回原序列memcpy(arr, sorted, len*sizeof(int...
num :51, value :5num :52, value :6num :50, value :7num :53, value :8num :49, value :10num :54, value :12num :48, value :16num :55, value :19num :47, value :24num :56, value :27num :46, value :33num :57, value :38num :45, value :45num :58, value :50num :...
const void *b){ int *p1=(int*)a; int *p2=(int*)b; return (*p1-*p2);}int main(){ int p[]={3,4,2,1,5}; int n=sizeof(p)/sizeof(int );//the number of items qsort(p,n,sizeof (int),compare1); cout<<"sorted array: "<<endl; for (int i=0;i<...
NULL on error. Even in case of error, the* list will be some permutation of its input state (nothing is lost or* duplicated).*//*[clinic input]list.sort*key as keyfunc: object = Nonereverse: bool = FalseSort the list in ascending order and return None.The sort is in-place...
#include <stdio.h> #include <stdlib.h> int compare(const void *a, const void *b) { return (*(int*)a - *(int*)b); } int main() { int arr[] = {9, 5, 7, 2, 4}; int n = sizeof(arr) / sizeof(arr[0]); qsort(arr, n, sizeof(int), compare); printf("Sorted arra...
("\n");}intisSorted(int*arr,intn){for(inti=0;i<n-1;i++){if(arr[i]>arr[i+1])return-1;}return0;}voidswap(int*a,int*b){inttemp=*a;*a=*b;*b=temp;}intpartition(int*arr,intleft,intright){intpivot=arr[left];inti=left;for(intj=i+1;j<=right;j++){if(arr[j]<pivot)...
#include <stdio.h> #include <stdlib.h> int compare(const void *a, const void *b) { return (*(int*)a - *(int*)b); } int main() { int arr[] = {5, 2, 8, 1, 6}; int n = sizeof(arr) / sizeof(arr[0]); qsort(arr, n, sizeof(int), compare); printf("Sorted arra...
If your data has a lot of partially sorted sequences, then Tim sort will beat the kilt off of anything else. Timsort is not as good if memory movement is many orders of magnitude more expensive than comparisons (like, many more than for normal int and double). If so, then quick sort...
实际的排序是由list.sort完成的。sorted只是根据给定的任何可迭代参数创建一个新的列表，就地排序该列表，...
I have an array that is sorted by the bubble method.I need sorting by even indices. I understand that this needs to be done through for (i = 2; i <20; i + = 2) but nothi