在表达式 *array 中,array 扮演的是指针,因此这个表达式的结果就是数组第 0 号单元的值。sizeof(*array) 测出的是数组单元的大小。表达式 array+n(其中n=0,1,2,...)中,array 扮演的是指针,故array+n 的结果是一个指针,它的类型是 TYPE *,它指向的类型是 TYPE,它指向数组第 n 号单元。故sizeof(array...
sizeof(array));//array size, 40 bytesprintf("%d\n",sizeof(c_p));//pointer size, 4 bytesprintf("%d\n",sizeof(c_array));//char array size, including the final char '\0', 7 bytes, different from function strlen, which ignoring the ending char '\0'return0;...
printf("Size of array arr: %zu bytes\n",sizeof(arr)); printf("Size of one element in arr: %zu bytes\n",sizeof(arr[0]));// 指针大小int*ptr = &a; printf("Size of pointer ptr: %zu bytes\n",sizeof(ptr));// 结构体大小structPerson {charname[50];intage; };structPerson person;...
void printIntPointerArray(char * arrayName, int * * pointerOfArray, int length) { // 如果在函数内用sizeof来获得函数外传入的数组长度,会发现数组退化成了指针,获得的只是指针的长度,因此要在函数外计算出数组长度再传进函数里 // printf("\nprintIntPointerArray() loading...\n"); // 打印指针数...
// Get the size of the myNumbers arrayprintf("%lu", sizeof(myNumbers)); Result: 16 Try it Yourself » How Are Pointers Related to ArraysOk, so what's the relationship between pointers and arrays? Well, in C, the name of an array, is actually a pointer to the first element of...
Pointer Address of a variable in memory Allows us to indirectly access variables in other words, we can talk about its address rather than its value Arrays: Array is a group of elements that share a common name, and that are different from one another by their positions within the array. ...
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int*ip;/* ip is a pointer to int */ ip=&x;/* ip now points to x */ y=*ip;/* y is now 1 */ *ip=0;/* x is now 0 */ ip=&z[0];/* ip now points to z[0] */ 1. 2. 3. 4. 5. 6. 变量x、y与z的声明方式我们已经在前面的章节中见到过。我们来看指针ip的声明,如...
marbles+SIZE 这里实际上使用了越界,但是后续表达更加方便简洁。 5. 指针操作 #include<stdio.h>intmain(void){inturn[5]={100,200,300,400,500};int*ptr1,*ptr2,*ptr3;ptr1=urn;//把urn的第一个地址赋给ptr1ptr2=&urn[2];printf("pointer value, dereferenced pointer, pointer address:\n");printf...