= 0) { remainder = n % 10; reverse = reverse * 10 + remainder; n /= 10; } if (original % 10 == 0) { printf("Reversed number = %d", reverse); while (original % 10 == 0) { printf("0"); original /= 10; } } else { printf("Reversed number = %d", reverse); } ...
C 语言实例 - 数字翻转 C 语言实例 用户输入数字,将数字进行翻转。 实例 [mycode3 type='cpp'] #include int main() { int n, reversedNumber = 0, remainder; printf('输入数字: '); scanf('%d', &n); while(n != 0) { remainder =.
C 语言实例 用户输入数字,将数字进行翻转。 实例 #include<stdio.h>intmain(){intn,reversedNumber=0,remainder;printf("输入数字:");scanf("%d", &n);while(n!=0){remainder=n%10;reversedNumber=reversedNumber*10+remainder;n/=10;}printf("翻转后 %d",reversedNumber);return0;} 运行结果: 输入数字:...
Write a C program to reverse and print a given number. Pictorial Presentation: Sample Solution: C Code: #include<stdio.h>intmain(){intnum,x,r_num=0;// Prompt user to input a numberprintf("Input a number: ");scanf("%d",&num);// Display the original numberprintf("\n...
编译并运行:$ cc string_reverse.c $ string_reverse.out 123456 abcdefg ABCD 654321 gfedcba DCBA $ string_reverse.out "123456 abcdefg ABCD" DCBA gfedcba 654321 1234567复制代码 可以看到各参数能够正常反转了!练习3-3,编写函数expand(s1,s2),对字符串速记符号进行扩展。编写...
c++ socket programming bind error C++ standards in Microsoft Visual C++ compilers c++ use an image as the background. C++ When my code asks for my full name it only gets my first name and not last C++/CLI DLL referencing MFC: mfcs140d.lib(dllmodul.obj) : error LNK2005: DllMain already...
Write a C programming to check whether a given integer can be expressed as the sum of any non-negative integer and its reverse. Return true otherwise false. Test Data: (554) -> 1 (51) -> 0 (55) -> 1 (181) -> 1 Click me to see the solution ...
if(reverse==n) printf("%d is a palindrome.",n); else printf("%d is not a palindrome.",n); return 0; } 结果输出: Enter an integer: 12321 12321 is a palindrome. 3、质数检查 注:1既不是质数也不是合数。 源代码: /* C program to check whether a number is prime or not. */ ...
short reverseInt (char ∗c) { int i; char ∗p = (char ∗)&i; /// 乾坤大挪移, 神龙摆尾, 隔山打牛 if (is_bigendian()) { p[0] = c[0]; p[1] = c[1]; p[2] = c[2]; p[3] = c[3]; } else { p[0] = c[3]; p[1] = c[2]; p[2] = c[1]; p[3]...
if(reverse==n) printf("%d is a palindrome.",n); else printf("%d is not a palindrome.",n); return 0; } 结果输出: Enter an integer: 12321 12321 is a palindrome. 3、质数检查 注:1既不是质数也不是合数。 源代码: /* C program to check whether a number is prime or not. */ ...