Dynamic Memory Allocation Example: In this C program, we will declare memory for array elements (limit will be at run time) using malloc(), read element and print the sum of all elements along with the entered elements.
// C program to calculate the sum of array elements// using pointers as an argument#include <stdio.h>intCalculateSum(int*arrPtr,intlen) {inti=0;intsum=0;for(i=0; i<len; i++) { sum=sum+*(arrPtr+i); }returnsum; }intmain() {intintArr[5]={10,20,30,40,50};intsum=0;...
int c, int *gt, int *sum);int main(void){int arr1[6], arr2[10], arr3[15], gt60A, gt60B, gt60C, sumA, sumB, sumC;getResult(arr1, 6, >60A, &sumA); /* userCode(<60字符): 调用函数读 6个数到arr1中,并计算和及>60的个数 */getResult(arr2, 10, >60B...
1 #include<stdio.h> 2 #define NUM 8 3 int main() 4 { 5 int arr[NUM],sum; 6 int i=0; 7 for(int i=0,sum=2;i<NUM;i++,sum*=2) 8 { 9 arr[i]=sum; 10 } 11 12 printf("The elements in the array are:"); 13 do 14 { 15 printf("%d ",arr[i]); 16 i++; 17 ...
int array[n]; //非法 因为标准C认为数组元素的个数n不是常量,虽然编译器似乎已经“看到”了n的值,但intarray[n]要在运行时才能读取变量n的值,所以在编译期无法确定其空间大小。使用符号常量定义数组长度的正确形式如下: #define N 10 int array[N]; ...
Address of array geo: 0x7fffffffddf6 [wenxue@hpi7 hellvsc]$ #include <stdio.h> #include <string.h> int main() { int i; char word[20], ans[20]; printf("Please Enter 6 letters: \n"); for(i = 0; i < (int) (sizeof(word)/2)+1; ++i) { ...
·在for中使用 函数定义: ·函数头:void(返回类型) sum(函数名)(int begin,int end)(参数表){函数体} ·调用函数·函数名(参数值);即使没有参数也需要();这些值会被按照顺序依次用来初始化函数中的参数 ·函数可知道哪里调用它,并回到调用它的下面那行去 ·调用函数时给的值与参数的类型不匹配自动转换 ...
#include "stdio.h" #define n 5 void out(int a[n][n] ); int he(int a[n][n]); void main() { int a[n][n],i,j,s; printf("input 5*5 elements\n"); for(i=0;i } he(int a[n][n]) { int i,sum=0; for(i=0;i 8...
4. Array CopyWrite a program in C to copy the elements of one array into another array.The task involves writing a C program to copy the elements from one array to another. The program will take a specified number of integer inputs to store in the first array, then copy these elements...
{2,4,5,6,8,9,11,15,17};int sum;sum=func(a);printf("sum= %d\n",sum);getch();}int func(int a[ ][3]){ int i,j,sum=0;for(i=0;i<3;i++)for(j=0;j<3;j++){ a[i][j]=i+j;if(i==j)sum=sum+a[i][j];}return(sum);}A.sum=6 B.sum=27 C.sum=25 D.sum=...