如果我们看一下以下定义: 除非它是sizeof运算符或一元&运算符的操作数,或者是用于初始化数组的字符串文字,否则类型为“array of type”的表达式将转换为类型为“pointer to type”的表达式,该表达式指向数组对象的初始元素,并且不是左值。如果数组对象具有寄存器存储类,则行为未定义。 看起来像是a类型从array of in...
data_type *pointer_variable; Initialization of pointer to array pointer_variable=&array_variable[0];ORpointer_variable=array_variable; Let’s consider the declaration and initialization of pointer to integer array 1) Declare integer array with the number of elements ...
Except when it is the operand of the sizeof operator or the unary & operator, or is a string literal used to initialize an array, an expression that has type ‘‘array of type’’ is converted to an expression with type ‘‘pointer to type’’ that points to the initial element of th...
// Get the memory address of the first array elementprintf("%p\n", &myNumbers[0]); Result: 0x7ffe70f9d8f00x7ffe70f9d8f0 Try it Yourself » This basically means that we can work with arrays through pointers!How? Since myNumbers is a pointer to the first element in myNumbers, ...
对于数组指针(pointer to array)的声明是这样: int (*pa)[5]; 可以这样使用: pa = &a; // 赋值(assignment)操作 int i = (*pa)[2]; // 将a[2]赋值给i; 2.有了上面的基础,我们就可以对付开头的三只纸老虎了!:) 这个时候你需要复习一下各种运算符的优先顺序和结合顺序了,顺便找本书看看就够了...
arr1 is an array of 8 pointers to integers. int (*arr2)[8]; 1. arr2 is a pointer (the parenthesis block the right-left) to an array of 8 integers. int *(arr3[8]); 1. arr3 is an array of 8 pointers to integers.
pointer为数组指针变量名 type为指向的数组的类型 n为指向的数组的大小 #include<stdio.h>typedefint(AINT5)[5];typedeffloat(AFLOAT10)[10];typedefchar(ACHAR9)[9];intmain() { AINT5 a1;floatfArray[10]; AFLOAT10* pf = &fArray; ACHAR9 cArray;char(*pc)[9] = &cArray;char(*pcw)[4] =...
意思是对于非数组和指针类型的变量，不能用[]这样的下标符号。下标表达式，形如p[i]，等价于*(p+i)，其中+是指针加法，数值上相当于+ sizeof(*p) * i。“多维”的下标表达式如p[i][j]，由结合性等价于(p[i])[j]，即*(p[i]+j)，也就是*(*(p+i)+j)。[]和一元*操作符的操作数...
这个错误通常是因为你在使用下标访问一个非数组或非指针类型的变量。检查一下你的代码吧 ...
The void pointer, also known as the generic pointer, is a special type of pointer that can be pointed at objects of any data type! A void pointer is declared like a normal pointer, using the void keyword as the pointer’s type: