int16_t 强转为uint16_t int32_t 强转为uint32_t#无符号转有符号如: uint8_t 强转为int8_t uint16_t 强转为int16_t uint32_t 强转为int32_t 举例: int32_t val = -121; uint32_t new = (uint32_t)val; printf("val = 0x%x, %d, new = 0x%x, %d\n", val, val, new, new);...
代码很简单,直接上源码: #include<stdio.h>typedefunsignedcharuint8_t;typedefunsignedintuint32_t;uint32_ttest_val=0x12345678;intmain(){printf("test init value is:0x%x\n\r",test_val);// expected resultuint8_tval1=test_val&0xff;uint8_tval2=(test_val&0xff00)>>8;uint8_tval3=(test_val...
NSData*data = [aString dataUsingEncoding:NSUTF8StringEncoding];//通过utf-8转为data9.NSData转Uint8+ (uint8_t)uint8FromBytes:(NSData *)fData { NSAssert(fData.length==1,@"uint8FromBytes: (data length != 1)"); NSData*data =fData; uint8_t val=0; [data getBytes:&val length:1];...
16.NSData转int16_t //bigEndian 传NO就行 +(int16_t) int16FromBytes:(NSData *)data bigEndian:(BOOL)bigEndian { NSUInteger len = [data length]; Byte *by=(Byte *)malloc(len); memcpy(by, [data bytes], len); int16_t ret=((by[1] & 0xFF) << 8) + (by[0] & 0xff); if...
int unicode_to_utf8(uint16_t *in, int insize, uint8_t **out) { int i = 0; int outsize = 0; int charscount = 0; uint8_t *result = NULL; uint8_t *tmp = NULL; charscount = insize / sizeof(uint16_t); result = (uint8_t *)malloc(charscount * 3 + 1); ...
unsigned int 类型4字节内容不能直接拷贝成//unsigned char类型的#include <stdio.h> 2 int main(int argc, const char *argv[]) 3 { 4 unsigned char a=9; 5 unsigned int b=0x12345678; 6 unsigned int c=0x87654321; 7 ··· 8 unsigned char dd[2][9]; ...
在C语言中，UINT8是一个重要的数据类型，它表示无符号8位二进制整型，本质上等同于unsigned char。当我们看到"(uint8 *)"这样的表示，实际上是将变量t的类型转换为指向无符号8位整数的指针类型。这里的"uint8"中的'u'代表无符号，'int'指的是整数，而'8'则表示占用8个字节。此外，'_t'通常...
请问uint8_t..目前官方函数库的读uart数据是uint32_t 的...UART_ReadByte(uint32_t * data)但我们使用的接收包是uint8_t位的...简单大概是这样int main(v
void ota_send_handler(uint8_t *pbuff, uint16_t len) //这里len我们用不到 { beken_ota_pkt_s* beken_ota_pkt= (beken_ota_pkt_s*)pbuff; } 四、强制转换之 struct---> u8 存储时一般变量定义在一个结构体里,要存入IIC时直接强转成(unsigned char*)类型,此时会自动将整个结构体按照1字节铺开...
intunicode_to_utf8(uint16_t*in,intinsize, uint8_t**out) { inti=0; intoutsize=0; intcharscount=0; uint8_t*result=NULL; uint8_t*tmp=NULL; charscount=insize/sizeof(uint16_t); result=(uint8_t*)malloc(charscount*3+1);