CArray<CPoint,CPoint> myArray; // Add elements to the array. for (int i = 0; i < 10; i++) myArray.Add(CPoint(i, 2*i)); // Modify all the points in the array. for (int i = 0; i < myArray.GetSize(); i++) { CPoint& pt = myArray.ElementAt(i); pt.x = 0; ...
int getArrayLen(T& array) {//使用模板定义一 个函数getArrayLen,该函数将返回数组array的长度 return (sizeof(array) / sizeof(array[0])); } int main() { char a[] = {'1','2','3'}; cout << getArrayLen(a) << endl; return 0; } 测试代码: #include<iostream>#include<cstring>usi...
在C++中可以用全局变量 template <classT>intgetArrayLen(T&array) {return(sizeof(array) /sizeof(array[0])); } 2.字符串数组char* (1)使用sizeof() sizeof(array)-1 (2)使用strlen(),计算字符开始直到第一个\0出现 (3)使用.size(),类似sizeof 有一些注意点: char* ss = "0123456789"; sizeo...
int length = sizeof(array)/sizeof(array[0]);这是因为sizeof(array)是取数组的字节数，而每个元素的字节数是sizeof(array[0])，所以，商才是数组中元素的个数。
int main(){ int arr[] = {1,2,3,7,8}; int size = sizeof(arr); cout << size; } I know that the above code will print the size of the array which is 4*5 = 20 bytes but i have a small doubt in this, arr is a pointer to the first element in the array and the size...
extern size_t x_count; In x.c add: size_t x_count = sizeof(X)/sizeof(x); Then use the variable x_count in your loop. The division has to be done in the compilation unit that contains the array initializer, so it knows the size of the whole array. Share Follow edited...
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array 表示数组首元素地址 , &array 表示数组地址 ; 假如array 是指针 , 则 sizeof(array) 是指针变量的大小 4 4 4 字节 , *array 是指针指向的元素 , sizeof(*array) 是指针指向的元素的大小 , sizeof(array) / sizeof(*array) 就是 4 数 据 类 型 大 小 \cfrac{4}{...
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示例2: cJSON_GetArraySize ▲点赞 7▼ voidJsonSchema::readItemAllOf(cJSON *allofValues, ItemsPtr item) {intsize =cJSON_GetArraySize(allofValues);intindex =0;do{ cJSON *childAllOf = cJSON_GetArrayItem(allofValues, index); cJSON *itemReference = cJSON_GetObjectItem(childAllOf,"$ref...