sizeof(array)/sizeof(type) But I can't seem to find out the length of the array passed as an argument to a function: #include <stdio.h> int length(const char* array[]) { return sizeof(array)/sizeof(char*); } int main() { const char* friends[] = { "John", "Jack", "J...
{return(sizeof(array) /sizeof(array[0])); }intmain() {charstr[]={'1','2','3','4'};//逐个字符赋给数组中元素charstr2[]={"1234"};//字符串赋给数组intstr1[]={1,2,3,4};//整型数组stringstr3[]={"23","3434"};//字符串数组stringstr4="2324242";//字符串cout<<getArrayLen...
cd-49 11511a cd-graphics demonstra cd-r cd-rom array cd-vcompact disc - vi cd-worm cd cdca-ich collision de cddvd drive cdac cdata cdatetimectrl cdacombined ddaapplic cdb commondatabus cdbac cdbonlinetime cdbpaymentlog cdbusergroups cdc us caccesss for d cdc us centers for di cdc-pdc...
come and get them come and join them come at the sound of come away come away d come back to the futu come conversion come cross come down in time come downfall come forth come home this instan come il primo tempo come in pursuit come in son come in view come into ear come into my...
GET_ARRAY_LENGTH(a,num); printf("%d\n",num);return0; } C++语言: #include<iostream>template<classT>intGetArrayLen(T&a) {returnsizeof(a)/sizeof(a[0]); }intmain() {chara[]={'1','2','3'};intnum =GetArrayLen(a); std::cout<<num<<std::endl;return0; ...
lenght = strlen(str); 这种方法只适用于字符串数组 使用while循环遍历计数 1 2 int i=0; while(str[i++] != '\0'); 这种方法适用于计算数组中实际元素多少 利用sizeof函数计算地址 1 len = sizeof(str)/sizeof(str[0]); 这种方法适用于计算数组分配的总长度多少,包括空字符...
My solution to this problem is to save the length of the array into a struct Array as a meta-information about the array. #include <stdio.h> #include <stdlib.h> struct Array { int length; double *array; }; typedef struct Array Array; Array* NewArray(int length) { /* Allocate...
arm_get_correlator_max_length() — Get the max length of the transaction correlator arm_get_timestamp() — Get the current timestamp arm_init_application() — Defines an ARM application arm_init_transaction_type() — Defines and initializes an ARM transaction type arm_start_transaction...
其中一种方法是使用sizeof(array) / sizeof(array[0]), 在C语言中习惯上在使用时都把它定义成一个宏,比如: #define GET_ARRAY_LEN(array,len) {len = (sizeof(array) / sizeof(array[0]));} 而在C++中则可以使用模板技术定义一个函数,比如: templateint getArrayLe ...
...注意,数组作为函数的参数进行传递的时候,该数组自动退化为指针,如: int arrsize(int array[]) { return sizeof(array); //永远都是4...,因为是int }C++中模板可以解决该问题(传入后数组不会退化) template int getArrayLen(T& array) { return... sizeof(array) / sizeof(array[0]); //可以...