Here is my code to find substring entered by the user in the given string. bool find_str(char *str, char const *substr) { while(*str) { if(*str++ == *substr) { char const *a = substr; while((*str++ == *++a)); /*empty*/ if(*a == '\0') return true; } } return ...
; char ch = 'o'; int result; result = findChar(str, ch); if (result != -1) { printf("Found '%c' at position %d\n", ch, result); } else { printf("'%c' not found in the string\n", ch); } return 0; } 复制代码 这两种方法都可以用来查找指定字符在字符串中的位置。第一...
1#include <stdio.h>234#defineTRUE 15#defineFALSE 067intfind_char(char**strings,charvalue);89char*str[] ={10"first",11"second",12"third"13};1415intmain(intargc,char*argv) {1617charc;18scanf("%c", &c);19if(find_char(str,c))20{21printf("%c in sourcestr\n", c);22}23else{2...
unsignedintFindStrIndex(char*Str,constchar*FindStr,constunsignedintFindStrPos){unsignedintStrLenth = StringLen(Str);unsignedintFindStrLenth = StringLen(FindStr);char*Sub =NULL;unsignedintIndex =0;unsignedintFindStrIndex =0; OP_STATUS Status = SUCCESS;printf("FindStrIndex start\n");if(Str ==NULL...
include "string.h"int main(void){ char str1[]="ab678ef0ABCDEcdNijklmnOPQghopqrs345FGHIJKLtuvwxyz12M9RSTUVWXYZ";//定义一个试验用字符串 char ch,*p;while(1){ printf("Input a character to find(# end)...\nch=");if(scanf(" %c",&ch),ch=='#')//输入要查找的字符,若...
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+ sizeof(vowel) / sizeof(vowel[0]); char* position = std::find(vowel, end, c...
在下文中一共展示了nsAFlatCString::FindChar方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。 示例1: readUntil /** * Consume characters until you find one contained in given ...
因为getline函数返回时丢弃换行符,换行符将不会存储在string对象中。 Prototype: ssize_t getline (char **lineptr, size_t *n, FILE *stream) Description: This function reads an entire line from stream, storing the text (including the newline and a terminating null character) in a buffer and stor...