但是,我收到错误 expression must have a constant value。 我的函数调用(在 main 中)如下所示: int* occurencesPtr = Mode(numbersPtr, mode, SIZE); 用SIZE 在文字的开头定义 20。 我知道该错误是因为函数的版本 SIZE 仅在调用函数时才获取其值(?),但我不知道如何解决这个问题。 我什至尝试将 const ...
下面的语句(第4行)有错:u16 rr=uy;错误的原因是定义变量的初始化值必须是常数,不能是变量,你可以修改为:u16 rr=9;
#include <stdio.h> void main(void) { double y; double x, a, b, c, result; printf("Enter value for y: \n"); scanf_s("%lf", &y); getchar(); { switch (y) { case (y > 0 & y <= 10): printf("y is equal or greater than 0 and smaller than 10"); break; case (y...
int main() { int size = 2; double array[size]; } Gives “expression must have a constant value”, Seems like the root cause is the same. 0 Feb 19, 2021 12:26 PM Feedback Bot Fixed - Pending Release··· A fix for this issue has been internally implemented...
In linux gcc, you can create an array and use a variable as size. When you try to do the same in Visual Studio, IntelliSense says that expression must have a constant value. I've researched about it, but it's still not clear to me why this happens in Visual Studio. Is the...
intsum(inta,intb) {returna + b; } _Static_assert(sum(3,4) ==7,"test #1"); 使用gcc 编译时会报错: gcc -c test.ctest.c:3:16: error: expression in static assertion is not constant_Static_assert(sum(3,4) ==7,"test #1"); ...
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switch( c ) {case'a':case'b':case'c':case'd':case'e':case'f': convert_hex(c); } 在此範例中,如果constant-expression等於'a'與'f'之間的任何字母,則會呼叫convert_hex函式。 Microsoft 專有 Microsoft C 不會限制switch陳述式中case值的數量。 此數目會受到可用記憶體的限制。 ANSI C 要求在...
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29: Do statement must have while — Do-while语句中缺少while部分30: Enum syntax error — 枚举类型语法错误31: Enumeration constant syntax error — 枚举常数语法错误32: Error directive :xxx — 错误的编译预处理命令33: Error writing output file — 写输出文件错误34: Expression syntax error — 表达式...