first off order of operations. the compiler is welcome to and should do the modulo first resulting in anint. Next order of operations, parenthesis would remove all doubt. the multiply is next but one operand is adouble (pow)so the result of the modulo has to be promoted todouble. and t...
union{intmyInt;floatmyFloat; } my_union; my_union.myInt =0x BFFFF2E5;printf("float is %f\n", my_union.myFloat);floatis-1.999600 You are telling the compiler to take the number you have (large integer) and make it into a float, not to interpret the number AS float. To do that, ...
unsigned int ui; unsigned int sum; // 错误 if (sum + ui > UINT_MAX) too_big(); else sum = sum + ui; // 正确 if (ui > UINT_MAX - sum) too_big(); else sum = sum + ui; 上面示例中,变量 sum 和 ui 都是 unsigned int 类型,它们相加的和还是 unsigned int 类型,这就有可能发...
编辑:2020-08-30:所以,我的用例将返回 double 的函数的值转换为 int,并选择 pow() 来表示该值 某处的私有函数。然后我更多地回避了 pow() 的思考。 (请参阅更多评论,了解为什么下面使用的 pow() 可能会出现问题...)。
// class type-casting #include <iostream> using namespace std; class CDummy { float i,j; CDummy():i(100),j(10){} }; class CAddition:public CDummy { int *x,y; public: CAddition (int a, int b) { x=&a; y=b; }
是的,整数值可以加到浮点值上。基本的数学运算(+,-,*,/),当给定一个类型为float和int的操作...
C风格类型转换(C-style type casting):这种类型转换使用类型名作为转换操作符,语法为(type)expression。例如,将整数转换为浮点数:float x = (float)int_value;。C风格类型转换是强制性的,它可能导致一些意想不到的结果,因为它允许将任意类型转换为另一种类型。在底层,C风格类型转换通常通过生成与隐式类型转换相似...
int i = static_cast<int>(d); 但static_cast已经有安全性的考虑了,比如对于不相关类指针之间的转换。参见下面的例子: 1 // class type-casting 2 #include <iostream> 3 using namespace std; 4 5 class CDummy { 6 float i,j; 7 };
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