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该函数以getaddrinfo返回的非0错误值的名字和含义为他的唯一参数,返回一个指向对应的出错信息串的指针。 6)由getaddrinfo返回的所有存储空间都是动态获取的,这些存储空间必须通过调用freeaddrinfo返回给系统,该函数原型为: void freeaddrinfo( struct addrinfo *ai ); ai参数应指向由getaddrinfo返回的第一个addrin...
(rsal = rd_getaddrinfo(broker, RD_KAFKA_PORT_STR, AI_ADDRCONFIG, AF_UNSPEC, SOCK_STREAM, IPPROTO_TCP, &errstr))) { rd_kafka_log(NULL, LOG_ERR, "GETADDR", "getaddrinfo failed for '%s': %s", broker, errstr); return NULL; } /* * Set up the handle. */ rk = calloc(1, s...
timeout on name lookup is not supported# getaddrinfo(3) failed for raw.githubusercontent.com:443# Couldn't resolve host 'raw.githubusercontent.com'# Closing connection 0# 错误文件夹 无法下载的文件 3. 解决方法 打开,找到正确版本的ffmpeg并下载。若网速太慢或不能下载可以参考。 opencv_3rdparty ...
status = getaddrinfo (host, NULL, &hints, &result); if (status) { __xmlIOErr(XML_FROM_HTTP, 0, "getaddrinfo failed\n"); return INVALID_SOCKET; } for (res = result; res; res = res->ai_next) { if (res->ai_family == AF_INET) { ...
但是当读到 goto _failed 时,产生疑惑因为 _failed:标号只有一个 close(fd); 由于之前没用过这个知识点,以为运行完close(fd)后会直接退出函数,因此疑惑为什么没有调用 getaddrinfo(...),还以为是作者的失误(...),但一想觉得又不可能是作者的问题,结果 查看 K&R<<C程序设计语言>>的相关内容,发现是自己的...
‼ getaddrinfo ENOENT raw.githubusercontent.com ‼ gifsicle pre-build test failed i compiling from source × Error: Command failed: C:\windows\system32\cmd.exe /s /c "autoreconf -ivf" 'autoreconf' �����ڲ����ⲿ���Ҳ���ǿ����...
# getaddrinfo(3) failed for raw.githubusercontent.com:443 # Could not resolve host: raw.githubusercontent.com # Closing connection 信息 上面的日志至少告诉我们如下信息:1. opencv_videoio_ffmpeg.dll的下载网址;2. 本地存放的路径;3. 需要校验md5。
I looked into the error codes and 0x5d000002f means "STATUS_SIGNALING_ICE_CONFIG_REFRESH_FAILED", 0x000000f means operation timeout and the error code "E: getaddrinfo failed: -2" means name or service are unknown. Could this have something to do with the libwebsocket library? Are there...
lookup_windows_test.go:148: failed to get local ip: dial udp: lookup golang.org: getaddrinfow: This is usually a temporary error during hostname resolution and means that the local server did not receive a response from an authoritative server. ...