How I write the code to find the max value of the array elements without comparing the last element to something outside the memory block?" You just need to setmaxbefore going into the loop to0. Then you compare ifarray[i]is greater thanmaxat each iteration. If it is,maxgets assigned...
6, 3, 8, 4}; int size = sizeof(array) / sizeof(array[0]); int max = array[0]; int min = array[0]; for (int i = 1; i < size; i++) { if (array[i] > max) { max = array[i]; } if (array[i] < min) { min = array[i]; } } printf("最大值:%d\n", max...
1.定义一个整型数组,例如`intnumbers[10]={1,2,3,4,5,6,7,8,9,10};`。 2.定义一个整型变量`max`用于保存当前找到的最大值,并初始化为数组的第一个元素,例如`intmax=numbers[0];`。 3.使用一个循环结构(如for循环)来遍历数组中的每个元素。在循环体中,我们需要判断当前元素是否大于`max`,如果是,...
I have this implementation, the result of this program is 100 but the correct answer is 103. is anyone knows what is wrong in this implementation or if there is a better way for Finding the maximum consecutive sum of integers in an array?
解析 find max(a,sizeof(a)/sizeof(int)) max=array[0],第一处,填入findmax函数,其中第一个参数肯定是数组名,第二个参数是数组长度,可以用sizeof(a)/sizeof(int)表示,第二处,找最大值,首先默认第一个元素是最大值,所以要填:max=array[0]
max=a[i]; } printf("minimum of array is : %d",min); printf("\nmaximum of array is : %d",max); } intmain() { inta[1000],i,n,sum; printf("Enter size of the array : "); scanf("%d",&n); printf("Enter elements in array : "); ...
findSecondMaxValueInArray(int a[], int n) { int i; // 数组元素索引(下标) int max1 = 0; // 最大值元素下标 int max2 = 0; // 次大值元素下标 for (i = 0; i < n; ++i) { if (a[max1] < a[i]) { max2 = max1; // 原来最大值为新的次大值 max1 = i; // 当前...
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imaxdiv() — Quotient and remainder for intmax_t ImportWorkUnit() — WLM import service index() — Search for character inet6_is_srcaddr() - Socket address verification inet6_opt_append() — Add an option with length "len" and alignment "align" inet6_opt_find() — Search for...