bool isnan( float arg ); (since C++11) bool isnan( double arg ); (since C++11) bool isnan( long double arg ); (since C++11) 确定给定的浮点数arg是否不是数字( NaN )。 参数 arg :浮点值 返回值 true 如果arg是 NaN ,否则 false 参考http://en.cppreference.com/w/cpp/numeric/math/is...
在C语言中,当计算结果为NaN时,可以使用isnan()函数来判断是否为NaN,然后进行相应的处理。 示例代码如下: #include <stdio.h> #include <math.h> int main() { double result = sqrt(-1); // 计算平方根,结果为NaN if (isnan(result)) { printf("计算结果为NaN\n"); } else { printf("计算结果...
在C语言中,可以使用`isnan()`函数来检查一个浮点数是否是`nan`。这个函数接受一个`float`或`double`类型的参数,如果该参数是`nan`,则返回非零值,否则返回0。 例如: ```c include <> include <> int main() { double x = NAN; if (isnan(x)) { printf("x is not a number\n"); } else {...
cordyline terminalisv core address core auxiliary heat e core barrel of double core binding oil core core cells array core competence culti core competitive theo core competive abilit core complexion inc core cutter method core discharge plenum core drill machine core dumped core electrons core grinder...
ca ele cord ca id ca ofzdouble lift ca ot choose but do ca professional certi ca r boxing ca rosario central ca tan lathe cacanny ca-mmt ca-npi cacallaccounting caac civil aviation a caair caal caas commonwealth arb caat computerassisted caat computer assiste cab air filter housin cab ...
checkArgument( permitsPerSecond > 0.0 && !Double.isNaN(permitsPerSecond), “rate must be positive”); synchronized (mutex()) { doSetRate(permitsPerSecond, stopwatch.readMicros()); } } 主要实现在SmoothRateLimiter中: @Override final void doSetRate(double permitsPerSecond, long nowMicros) { ...
template <typename T> void myfunc(T h) { } template<> static void myfunc(double h) // static is ignored { } 類別範本內 static_assert 中所使用的常數將一律失敗。 下列程式碼會導致 static_assert 一律失敗: C++ 複製 template <size_t some_value> struct S1 { static_assert(false, "default...
template <typename T> void myfunc(T h) { } template<> static void myfunc(double h) // static is ignored { } 在类模板内的 static_assert 中使用的常量始终都会失败。 在下面的代码中,static_assert 始终都会失败: C++ 复制 template <size_t some_value> struct S1 { static_assert(false, "...
我正在为java eclipse mars中的二次公式编写一个函数,当我编译代码时,它会输出NaN,而从数学上讲,这个答案是可能的,我应该会得到2.0的帮助。 import java.util.Scanner; public class Quadradic1 { public static void main(String[] args) { double a; double b; double c; double x; System.out.print("...
__fwriting() — Determine if last operation on stream is a write operation fwscanf(), swscanf(), wscanf() — Convert formatted wide-character input gai_strerror() — Address and name information error description gamma() — Calculate gamma function gcvt() — Convert double to string ...