第一篇:c语言程序设计现代方法(第二版)习题答案 Chapter 2 Answers to Selected Exercises 2.[was #2](a)The program contains one directive(#include)and four statements(three calls of printf and one return).(b)Parkinson's Law: Work expands so as to fill the time available for its completion....
c语言程序设计现代方法(第二版)习题答案 下载积分:600 内容提示: Chapter 2 Answers to Selected Exercises 2. [was #2] (a) The program contains one directive (#include) and four statements (three calls of printf and one return) . (b) Parkinson' s Law: Work expands so as to fill the ti...
C语言程序设计现代方法(第二版)习题答案.docx,时磊忖呎… Chapter 2 An swers to Selected Exercises [was #2] (a) The program contains one directive (#inelude) and four statements (three calls of printf and one return). (b) Parkinsons Law: Work expands so as t
Chapter 2 Answers to Selected Exercises 2. [was #2] (a) The program contains one directive (#include) and four statements (three calls of printf and one return) . (b) Parkinson' s Law: Work expands so as to fill the time available for its completion. 3. [was #4] #include <stdio...
【精品】c语言程序设计现代方法(第二版)习题答案 下载积分:720 内容提示: Chapter 2 Answers to Selected Exercises 2. [was #2] (a) The program contains one directive (#include) and four statements (three calls of printf and one return) . (b) Parkinson' s Law: Work expands so as to fill...
#include <stdio.h> int main(void) { int i, j, k; float x, y, z; printf("Value of i: %d\n", i); printf("Value of j: %d\n", j); printf("Value of k: %d\n", k); printf("Value of x: %g\n", x); printf("Value of y: %g\n", y); printf("Value of z: %g\...
C语言程序设计现代方法第2版 作者:k.k.king 译者:吕秀峰 黄倩 编程题3.2习题答案 本人学习期间,分享习题答案。有不到之处,还望指正。 /*格式化输出产品编号、价格、生产日期*/ #include<stdio.h> int main() { int number; printf("Enter item number:"); ...
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2.[was#2](a) The program contains one directive (#include) and four statements (three calls of printf and one return). (b) Parkinson's Law: Work expands so as to fill the time available for its completion. 3.[was#4] #include <stdio.h> int main(void) { int height= 8,length= ...
6.char c[15]; 7. 8.printf ('Enter phone number: '); 9. 10.//输入字符直到为回车为止 11.while ((ch = getchar ()) != '\n') { 12.//输入的如果是字母,换成数字 13.if (ch <= 'Z' && ch >= 'A') { 14.switch (ch) { ...