代码：//讲src当中的数字字符转换成数字并存到des当中 //返回数字个数 int Change(int* des, const char* src){ int i, ret = 0, len = strlen(src);for(i=0; i<len; i++){ if('0' <= src[i] && '9' >= src[i]){ des[ret++] = src[i]-'0';} } return ret;}voi...
(stderr, "%s\n", error); exit(-1); } int atoi(const char *str) { if (str[0] == '\0') raise("invalid input: empty string"); int64_t r = 0; int64_t sign = 1; int i = 0; if (str[0] == '-') { sign = -1; i++; } for (; str[i] != '\0'; i++) {...
include <stdio.h>const int MAX = 1024;int main() {int i,n = 0,num,a[MAX];char filename[] = "indata.txt";FILE *fin = fopen(filename,"rt");if(fin == NULL) {printf("无法打开数据文件:%s\n",filename);return 1;}while(fscanf(fin,"%d",&num) == 1) {a[n++] ...
aotl atoll
//利用ASCII //此版本只能处理1位数。需要处理多位数请追问 int x,y,z;char input[5];do { gets(input);}while(3 != strlen(input));x=input[0]-'0'-1;y=input[1]-'a';z=input[2]-'0'-1;//Array[x][y][z]//PS.你追问里1a4应该映射成003吧？
C语言中int转字符数组 #include <stdio.h> #include <math.h> intmain() { charstr[80]; sprintf(str,"Pi 的值 = %f",M_PI); puts(str); return(0); } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 输出 Pi 的值=3.141593...
因为ASC码48就是'0'，也就是说'0'的值是48，而后依次是'1'到'9'。这样正好是char型减去48就是它对应的int值 不过这样写不好理解，直接写成str[i]-'0'就好。
方法2：int a[10]={65,66,67,68,69,70,71,72,73,74}; char buf; string s; for(int i=0;i<10;i++) { buf=a[i]; s+=buf; } 方法3：int a[10]={0,1,2,3,4,5,6,7,8,9}; char buf; string s; for(int i=0;i<10;i++) { buf=(char)a[i]+48; s...
long int a =12345;char string[10]={0};sprintf(string,"%ld",a); //%ld ---对应long int printf("%s\n",string);
include<stdio.h>#include<string.h>#include<stdlib.h>void IntToStr(int *i, char *c, int len){//i为整形数组，c为要存放字符串的数组，len为整形数组元素个数 int k; char tmp[10]; for(k=0;k<len;k++) { itoa(i[k],tmp,10); strcat(c,tmp); }}int...