Type: Bug Have a templated map or set type, such as: #include template <class T> bool val_in_map(std::map<T, char>& x, T val){ std::map<T, char>::iterator it = x.find(val); return it != x.end(); } The variable it will be <error-typ...
vector没有模版参数,std::vector<type>::iterator type处必须写一个类型,其他的一样
你把那个函数的形参const vector<int>vector后面的变量名Vector改成别的，（不能和关键字重名）再把函数体内的该变量名改过来，应该就可以通过编译了。
请问您的意思是这个报错是出现在启动VS的时候吗？还是出现在运行某个项目的时候？
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1> g:\project\rewptis\rewptis\rewptis.cpp(192): note: 参见对正在编译的函数 模板 实例化“cv::debug_build_guard::_InputArray::_InputArray<cv::KeyPoint>(conststd::vector<cv::KeyPoint,std::allocator<_Ty>> &)”的引用 1> with
The circumstances in my case were that the "vector <int> example;" line was accurate, the stdafx.h and vector directive(s) (as well as namespace std;) were in tact but I was still finding "..example is 'undeclared'"The issue in my case was that "..stdafx.h" was not the first...
报错: Line 3: Char 15: error: expected parameter declarator vectora(31,-1); 报错解释:编译器无法区分该语句是成员变量声明还是成员函数声明 解决方法 方法:利用vector的赋值构造函数 class Solution { public: vector<int> a=vector<int>(31,-1);// 修改后 ...
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