using namespace std; typedef struct BinaryTreeNode { int data; struct BinaryTreeNode *Left; struct BinaryTreeNode *Right; }Node; //创建二叉树,顺序依次为中间节点->左子树->右子树 Node* createBinaryTree() { Node *p; int ch; cin>>ch; if(ch == 0) //如果到了叶子节点,接下来的左、右子...
#include <stdlib.h>#include<stdio.h>#include"BinaryTree.h"intmain(void) { BinaryTree tree={0}; BinaryTreeCreate(&tree,7,10);//first leveladdLeftNodeByIndex(&tree,2,9,1); addRightNodeByIndex(&tree,3,6,1);//second leveladdLeftNodeByIndex(&tree,4,8,2); addRightNodeByIndex(&tree...
c'())'()(listc(create-binary-tree(string-appendpos"-L"))(create-binary-tree(string-appendpos...
#include <iostream> using namespace std; typedef struct node { char data; struct node *lchild,*rchild; }BiTNode,*BiTree; BiTree pre_mid_createBiTree(char *pre,char *mid,int len) //前序中序还原建立二叉树 { if(len==0) return NULL; char ch=pre[0]; //找到先序中的第一个结点 int...
using std::string; using std::max; using std::pair; using std::function; using std::queue; 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 异常类定义 class treeEmpty { public: treeEmpty(const char* theMessage = "The tree is empty") :message(theMessage...
树状数组(Binary Indexed Tree,简称BIT或Fenwick Tree)是一种用于高效处理数据序列的算法数据结构。它能够支持两个主要操作:单点更新和区间求和,这两个操作的时间复杂度都能达到O(log n),其中 n 是数据序列的长度。树状数组非常适合处理那些需要频繁更新和查询区间和的问题。
using namespace std; class N { //node declaration public: int k; N *l, *r; bool leftTh, rightTh; }; class ThreadedBinaryTree { private: N *root; public: ThreadedBinaryTree() { //constructor to initialize the variables root= new N(); ...
完整代码见dsa/Binary_Tree.cpp at main · Apocaly-pse/dsa (); 声明部分 #ifndef BTREE #define BTREE #include <iostream> #include <queue> #include <stack> #include <vector> #include <functional> // 递归lambda using namespace std; ...
root->right, level+1); } } // 打印二叉排序树 void print_binary_search_tree(Node ...
#include<iostream> #include<algorithm> using namespace std; typedef long long ll; const int N=5e5+5; struct node{ int val,pos; }a[N]; int c[N]; int n; ll ans; int lowbit(int x){//c[i]的区间长度,就是管着几个a[i] return x&(-x); } bool cmp(node A,node B){ if(A...