Filename or path not found. Parameters path File or directory path mode Permission setting Remarks When used with files, the _access function determines whether the specified file exists and can be accessed as specified by the value of mode. When used with directories, _access determines only wh...
10 fstream _file; 11 _file.open(FILENAME, ios::in); 12 if(!_file) 13 { 14 cout<<FILENAME<<"没有被创建!"<<endl; 15 } 16 else 17 { 18 cout<<FILENAME<<"已经存在!"<<endl; 19 } 20 21 cin.get(); 22 return 0; 23 } 方法二:利用C语言库函数(_access) 函数原型: int _acce...
2 #include <fstream> 3 4using namespace std;5 6#define FILENAME "*.dat" // 指定⽂件名 7 8int main( void )9 { 10 fstream _file;11 _file.open(FILENAME, ios::in);12if(!_file)13 { 14 cout<<FILENAME<<"没有被创建!"<<endl;15 } 16else 17 { 18 cou...
C/C++中判断某一文件或目录是否存在1.C++很简单的一种办法:#include#includeusingnamespacestd;#defineFILENAME"stat.dat"intmain(){fstream_file;_file.open(FILENAME,ios::
#define FILENAME "stat.dat" int main() { fstream _file; _file.open(FILENAME,ios:: in ); if ( ! _file) { cout << FILENAME << " 没有被创建 " ; } else { cout << FILENAME << " 已经存在 " ; } return 0 ; } 2.利用 c 语言的库的办法: ...
fstream _file; _file.open(FILENAME,ios::in); if(!_file) { cout<<FILENAME<<"没有被创建"; } else { cout<<FILENAME<<"已经存在"; } return 0;} 2.利用 c 语言的库的办法: 函数名: access 功能: 确定文件的访问权限 用法: int access(const char *filename, int amode); 以前一直没用过...
fstream _file; _file.open(FILENAME,ios::in); if(!_file) { cout<<FILENAME<<"没有被创建"; } else { cout<<FILENAME<<"已经存在"; } return0; } 2.利用 c 语言的库的办法: 函数名: access 功能: 确定文件的访问权限 用法: int access(const char *filename, int amode); ...
1.C++很简单的一种办法: #include <iostream> #include <fstream> using namespace std; #define FILENAME "stat.dat" int main() { &nb...C/C++中判断某一文件或目录是否存在 C/C++中判断某一文件或目录是否存在 1.C++很简单的一种办法: #include <iostream> #include <fstream> using namespace std...
fstream _file; _file.open(FILENAME,ios::in); if(!_file) cout<<FILENAME<<"没有被创建"; else cout<<FILENAME<<"已经存在"; return 0; 2.利用 c 语言的库的办法: 函数名: access 功能: 确定文件的访问权限 用法: int access(const char *filename, int amode); ...
If you do not pro- vide the complete file path as part of the parameter or add additional search directories, cc219x looks for input in the current directory. Using the verbose output switches for the preprocessor, compiler, assembler, and linker causes each of these tools to echo the name...