你好，你使用string类型。却没有包含头文件。建议添加：#include <string>，再试试。
std::string to_string(double value); std::string to_string(long double value); 举例: #include<iostream>// std::cout#include<string>// std::string, std::to_stringusingnamespacestd ;intmain(){ std::string pi ="pi is "+ std::to_string(3.1415926); std::string perfect = std::to_s...
"%d", ss); string s(temp); //调用string的方法 cout<<s.c_str()<<endl;/...
std::to_string 由于格式化目的依赖本地环境,从而从多个线程同时调用 std::to_string 可能会导致调用的部分序列化结果。 C++17 提供高性能、不依赖本地环境的替用品 std::to_chars。 示例 运行此代码 #include <iostream> #include <string> int main() { double f = 23.43; double f2 = 1e-9; double...
I am using the itoa() function to convert an int into string, but it is giving an error: undefined reference to `itoa' collect2: ld returned 1 exit status What is the reason? Is there some other way to perform this conversion? c Share Follow edited Dec 25, 2017 at 11:38 Peter...
#include<stdio.h>#include<string.h>#define N 20#define M 80#define FMT(x) "%"STR (x)"[^\n]%*c"#define STR(x) #xintgetstr(char(*t)[M+1]){printf("Enter strings, an empty string to end\n");intn=0;for(;scanf(FMT(M),t[n])==1;n++);returnn;}char*findmin(char(*a...
由于line不含换行符,若要逐行输出需要自行添加。照常,我们用endl来输出一个换行符并刷新输出缓冲区。 Thenewline that causesgetlineto return is discarded; it does not get stored in thestring. 由于getline函数返回时丢弃换行符,换行符将不会存储在string对象中。
I'm trying to add a string to the next index of my array, however I'm having this odd issue where when Im adding to any index other than 1 (yes, I'm indexing my array from one, just to match the actual number of the item for simplicity, I'm sorry!). Essentially, if I ass ...
char *str = "test";//指针指向一个字符串 printf ("%s\n", str);//输出str指向的字符串 2、使用puts函数进行输出，如 char *str = "test";puts(str);//输出str指向的字符串，会自动多输出一个换行 3、使用自定义函数进行输出，如 void myPuts(char *str)//自定义输出函数 { if (!