buy and sell stocks 在leetcode现在总共有5 道题。 Best Time to Buy and Sell Stock 这道题是基础,只能transaction一次,所以我们用 Best Time to Buy and Sell Stock II 这道题表示可以一直transaction,所以只需要下一次比上一次高,那就加一次。 Best Time to Buy and Sell Stock with Cooldown 这道题属...
Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before ...
股票买卖最佳时机leetcode 买卖股票的最佳时机-2 假设您有一个数组,其中第 i 个元素是给定股票在第 i 天的价格。 设计一个算法来找到最大的利润。 您可以根据需要完成任意数量的交易(即多次买入和卖出一股股票)。 但是,您不得同时进行多项交易(即,您必须先卖出股票,然后才能再次购买)。
股票买卖最佳时机leetcode-best-time-to-buy-and-sell-stocks:Java程序选择在给定的股票价格数组中买卖Su**剩余 上传1KB 文件格式 zip 系统开源 股票买卖最佳时机leetcode 买卖股票的最佳时机 Java 程序选择在给定的股票价格数组中买卖股票的最佳时间。点赞(0) 踩踩(0) 反馈 所需:1 积分 电信网络下载 ...
leetcode--Best Time to Buy and Sell Stock II 1.题目描述: Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share ...
Best time to buy and sell stocks IV 题目 https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit....
:rtype: int"""res=0foriinrange(1,len(prices)): temp= prices[i] - prices[i-1]iftemp <=0:continueelse: res+=tempreturnres 参考: 下面的更快,因为索引查找的次数少一些! classSolution(object):defmaxProfit(self, prices):""":type prices: List[int] ...
View Code 别人代码: View Code 学习之处: diff的变量命名不错 if(null==stocks || stocks.length==0) return 0; int maxProfit = 0 ; int cur = stocks[0]; for(int stock : stocks){ if(stock > cur) maxProfit += (stock-cur);