Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in mul...
leetcode ——Best Time to Buy and Sell Stock II 遍历价格vector,把每段上升期间的利润加起来,注意最后结束时记得再计算最后一次的利润 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 classSolution { // 把每段上升期间的利润加起来 // minVal: 低谷值 // m...
LeetCode 0122. Best Time to Buy and Sell Stock II买卖股票的最佳时机 II【Easy】【Python】【贪心】【动态规划】 Problem LeetCode Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as man...
在计算第一个时,因为sell之前没有buy因此只能从第一个元素开始,buy的第一个设置为-prices[0],sell和presell设置为0,这样就可以计算第一个元素的buy。 另外还有一道比较类似的robber题目:https://leetcode.com/problems/house-robber/?tab=Description。思路还是应用一个序列,只不过stock里面要考虑以...
Best Time to Buy and Sell Stock III 仅仅能操作两次时: 两次操作不能重叠。能够分成两部分:0...i的最大利润fst 和i...n-1的最大利润snd 代码例如以下: int maxProfit(vector<int> &prices) { if (prices.size() == 0) return 0; int size = prices.size(); ...
LeetCode编程练习 - Best Time to Buy and Sell Stock II学习心得,程序员大本营,技术文章内容聚合第一站。
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 122. 买卖股票的最佳时机 II 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天...
LeetCode121. Best Time to Buy and Sell Stock JonesM https://leetcode.com/problems/best-time-to-buy-and-sell-stock/leetcode.com/problems/best-time-to-buy-and-sell-stock/ 解题思路 1. 暴力 O(n2) 复杂度,超时 class Solution { public: int maxProfit(vector<int>& prices) { int maxVal...
class Solution: def maxProfit(self, prices: List[int]) -> int: ## 双指针解法 left, right = 0, 1 # left=buy, right=sell maxP = 0 while right < len(prices): ## 遍历整个 list if prices[right] > prices[left]: ## 在存在赚钱机会的条件下 profit = prices[right] - prices[left] ...
However, you maynotengageinmultiple transactionsatthesametime(ie, you must sellthestockbeforeyou buy again). 分析 其实很简单的一道题嘛,一开始想复杂了…… 举了栗子: // 4 7 8 2 8 最大利润很明显是 (8 - 4) + (8 - 2)=10 就因为这个式子让我想复杂了:首先要找到一个极小值4,然后找到极...