BUUCTF---RSA2 1.题目类型:dp泄露 点击查看代码 import gmpy2 as gp e = 65537 n = 2482540078515262411777215266989018029858327661762216096122588773716205800604331015383280303052199186976436198142009306796121098855338013353484450237516704784370730555447242806847332980515991676603036451831461614974853586336814921296688024020657977899...
1importgmpy22importhashlib34deftransform(x, y):#使用辗转相处将分数 x/y 转为连分数的形式5res =[]6whiley:7res.append(x //y)8x, y = y, x %y9returnres101112defcontinued_fraction(sub_res):13numerator, denominator = 1, 014foriinsub_res[::-1]:#从sublist的后面往前循环15denominator, num...
在RSAwienerHacker.py结尾处写上: if__name__ =="__main__": N =101991809777553253470276751399264740131157682329252673501792154507006158434432009141995367241962525705950046253400188884658262496534706438791515071885860897552736656899566915731297225817250639873643376310103992170646906557242832893914902053581087502512787303322747780420210884852166586717636559058152...
d=gmpy2.invert(e,phi) print(d) print(hex(d)) #hex(d)='0x13b8f87d588e2aa4a27296cf2898f56ab4c8deb5a1222ec080e23afecaf7f975' ''' 但python3中hex(d)得到的数字最后没有L,导致hash值与python2得到的不同,而正确的flag是用python2得到的结果,所以这里我手动加上了L''' print(hashlib.md5(...