publicclassSort{publicstaticvoidmain(String[]args){int[]unsortedArray=newint[]{6,5,3,1,8,7,2,4};bubbleSort(unsortedArray);System.out.println("After sort: ");for(intitem:unsortedArray){System.out.print(item+" ");
对于降序排序，则只需要调整相邻元素比较的逻辑，将判断从大于号转换为小于号，即可实现列表的逆序排序。在处理实际问题时，比如LeetCode 283E 移动0问题，要求将列表中的元素0全部移动到列表的最右边，其他元素位置不变。虽然冒泡排序在处理这类问题中并不高效，但由于其简洁的实现方式，对于理解和学习算法...
Sort-Algorithm 1057.Campus-Bikes.md 969.Pancake-Sorting.md Bubble-Sort.md Merge-Sort.md Quick-Sort.md README.md Stack String Toposort Trie-Tree Two-Pointers Union-Find .gitignore README.md SUMMARY.md book.json Breadcrumbs leetcode /Sort-Algorithm / Bubble-Sort.md Latest commit Chasel add...
hdu-5775 Bubble Sort(树状数组) 题目链接: Bubble Sort Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Problem Description P is a permutation of the integers from 1 to N(index starting from 1). Here is the code of Bubble Sort in C++. for(int i=1;i...
补充2:解法3 关键记忆:len(lis)-1 defbsort(lis):foriinrange(len(lis)-1):# 一般是 range(len),但是与右1的数字对比,所以少了一个位置forjinrange(len(lis)-1-i):iflis[j]>lis[j+1]:lis
Talk is cheap.Show me your code: 1func bubbleSort(_ array: inout [Int]){2ifarray.isEmpty {return}3varlastExchangeIndex:Int =04//无序数列的边界,每次比较只需要比到这里为止5varsortBorder:Int = array.count -16foriin0..<array.count -17{8//有序标记,每一轮的初始是true9varisSorted:Bool ...
bubble sort 算法 1 2 4 5 6 7 a=[80,46,21,18,79,78,95,7,91,4] length=len(a) foriinrange(length): forjinrange(length-1-i): ifa[j]>a[j+1]: a[j],a[j+1]=a[j+1],a[j] print(a)
bubble sort 算法 length = len(a) for i in range(length): for j in range(length-1-i): if a[j]>a[j+1]: a[j],a[j+1]=a[j+1],a[j] print(a) 1. 2. 3. 4. 5. 6. 7.
quicksort.kt ternary_search.kt LeetCode Linear Search in Matrix Linked List MathematicsDS Matrix PrefixSum ProjectEuler Recursion STL Searching Segment Tree Sorting Square Root Decomposer Stack Complete Operation Stack String Tree Tries Union Find array class class_JAVA cses express-dry graphs images ma...
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