staticvoidMain(string[] args) {int[] intArray = {3,6,4,2,5,1}; Bubble_Sort(intArray);foreach(variteminintArray) { Console.WriteLine(item); } Console.ReadLine(); }staticvoidBubble_Sort(int[] unsorted) {inttemp;for(inti =0; i < unsorted.Length - 1; i++) {for(intj =0; j...
public static void sort(int array[]){ int tmp = 0; //记录最后一次交换的位置 int lastExchangeIndex = 0; //无序数列的边界,每次比较只需要比到这里为止 int sortBorder = array.length - 1; for(int i = 0; i < array.length; i++){ //有序标记,每一轮的初始是true boolean isSorted = ...
Bubble Sort 是一种思路很简单的排序方法。 冒泡的泡是指当前待排序的序列中元素最大的那个元素,我们找到这个元素,并把这个元素放到最后一个位置,那么最大的元素就已经排好序了(冒泡了)。 这时候再将剩下的元素序列用同样的方法处理,就会出现所有元素中第二大的元素冒泡,第3大的元素冒泡,一直到最后一个元素不...
Bubble sorting is the very commonly and widely used sorting technique in C++ programming. It is also known as the exchange sort. It repeatedly visits the elements of an array and compares the two adjacent elements. It visits the array elements and compare the adjacent elements if they are not...
1单片机中定义flag有啥作用flag=1和flag=0都是什么意思void bubble_sort(int array[],int n) { int i,j,flag,temp; for(i = 0; i < n-1; i++) { flag = 1; for(j = 0; j < n-i-1; j++) { if(array[j] > array[j+1]) { temp = array[j]; array[j] = array[j+1]; ar...
冒泡排序(Bubble Sort),是一种计算机科学领域的较简单的排序算法。 这个算法的名字由来是因为越大的元素会经由交换慢慢“浮”到数列的顶端(升序或降序排列),就如同碳酸饮料中二氧化碳的气泡最终会上浮到顶端一样,故名“冒泡排序”。 算法原理 冒泡排序算法的原理是: 重复地走访过要排序的元素列,一次比较两个相邻的...
Therefore, to sort 'n' elements using the previous step, we require an 'n-1' pass. After following these steps, the largest element goes to the end of the array. The next largest is one place behind the last. The 'kth' largest element is swapped to its rightful place in the array ...
我的情况如下：import java.util.Arrays; public class BubbledSort { public static void sort(...
In Bubble sort, two consecutive elements in a given list are compared and their positions in the given list (array) are interchanged in ascending or descending order as desired. Consider the following series of numbers, which are to be arranged in ascending or descending order. The series of...
fun bubbleSort(a: Array<Int>) { val n = a.size (1..n - 1).map { val round = it for (j in 0..n - 1 - round) { if (a[j] > a[j + 1]) { val max = a[j] a[j] = a[j + 1] a[j + 1] = max }