该节点为叶子节点62if(node.isLeaf()){63//寻找当前节点所有关键字64ResultSearch result =divideSearch(node.getKeys(), key);65//查询结果:成功 返回已经存在关键字位置66if(result.result ==true){6768}else{//查询结果:失败 返回插入位置69node.insertKey(key, result.index);70}7172}else{73//寻找当前...
// 从BTree中删除给定的元素func(t*BTree)Delete(item Item)Item{returnt.deleteItem(item,removeItem)}func(t*BTree)deleteItem(item Item,typ toRemove)Item{// 如果树为空或者根节点中没有元素,直接返回,因为这种情况待删除的元素肯定不存在ift.root==nil||len(t.root.items)==0{returnnil}t.root=t.ro...
另外,background build index,可能会重复插入索引,因为doc数据可能会在磁盘上移动,也就是会被重复扫描到。 remove remove比insert就简单多了,因为remove是不可能失败的 find 找到后返回RecordID update 对比先后两个对象,计算出diff,包括需要删除的和需要增加的,然后批量提交修改。注意,这里可能会失败,但是失败后索引没...
offsets = insert(offsets, entryCount, x, offset); // 重新计算 offsets，写磁盘就按照 offsets...
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n.items.insertAt(i, item) // 把second插入i+1位置的children n.children.insertAt(i+1, second) return true}`这个地方可以想象出来一个树会比较好理解。执行完分裂之后再执行递归插入操作即可 执行递归插入 删除元素 删除元素的场景会稍微复杂一些,涉及到节点的合并 func (n *node) remove(item Item, min...
publicE removeKey(intindex) { E key =keys.remove(index); n--; returnkey; } publicvoidinsertChild(intindex, BTNode child) { children.add(index, child); if(children.size() >maxKeyNum+ 1) { children.remove(maxKeyNum+ 1); } }
root.insertNonFull(k); } } private void remove(int k) { if (root == null) { System.out.println("The tree is empty\n"); return; } // Call the remove function for root root.remove(k); // If the root node has 0 keys, make its first child as the new root ...
Index index = indexes.get(i);// 对应的,如果发生任何异常,会移除对应的索引数据。index.remove(session, row); } }throwde; } } ①同Mysql InnoDB 数据存储一样, RegularTable 必有,且只有一个聚集索引。以主键(或者隐含自增id)为key, 存储完整的数据。