inOrder(root);returnroot; }privatevoidinOrder(TreeNode node){if(node ==null){return; } inOrder(node.right);//先右sum+=node.val; node.val =sum;inOrder(node.left);//后左 } } 中序遍历的镜像 4. 二叉查找树的最近公共祖先 235. Lowest Common Ancestor of a Binary Search Tree (Easy) ...
Inorder Successor in BST Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, returnnull. 1/**2* Definition for a binary tree node.3* struct TreeNode {4* int val;5* ...
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 路径入栈法 复杂度 时间O(N) 空间 O(N) 思路 题目给定根节点和目标节点。目标节点如果有右节点的情况比较好处...
Explanation: There is no in-order successor of the current node, so the answer is null. Note: If the given node has no in-order successor in the tree, return null. It's guaranteed that the values of the tree are unique. 1. 2. 3. 4. 5. 6. 7. 8. 9. 第一次做; 利用BST的性...
LeetCode106. 从中序与后序遍历序列构造二叉树 题目来源: https://leetcode-cn.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/ 题目描述: 代码如下: ...【学习笔记】ApiPost调试api接口并快速生成接口文档的一些小技巧 ApiPost是一款兼顾api接口调试(postman的主要功能)和接口文档...
✨ a bunch of algorithms in a bunch of languages ✨ javascriptpythonjavadartrusttreealgorithmlinked-listalgorithmsleetcodegraphsolutionsarrayhackerrankbacktrackingdata-structuresleetcode-solutionsdynamic-programmingbsthackerrank-solutions UpdatedNov 6, 2022 ...
Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Given tree = [2,1] and node = 1: 2 / 1 return node 2. Given tree = [2,1,3] and node = 2: 2 / \ 1 3 return node 3. 解题思路 successor变量记录root的父亲结点,当while...
查询index部分可以使用Map做查询,建议和下一道题 leetcode 106. Construct Binary Tree from Inorder and Postorder Traversal 中后序构造BST和leetcode 449. Serialize and Deserialize BST 二叉搜索树BST的序列化和反序列化一起学习。 建议和leetcode 87. Scramble String 字符串拼凑 && DFS深度优先搜索 和 leetco...
LeetCode[285] Inorder Successor in BST Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. Iteration
1008 Construct Binary Search Tree from Preorder Traversal Valid/Unique 98 Validate Binary Search Tree 96 Unique Binary Search Trees 95 Unique Binary Search Trees II Delete/Insert/Count 701 Insert into a Binary Search Tree 222 Count Complete Tree Nodes 450 Delete Node in a BST 669...