bitXor - x^y using only ~ and & 然后代码如下: intbitXor(intx,inty)//使用~和&完成异或操作{return~(~x&~y)&~(x&y); } 本人想了一下如何推导,却没有办法很快推导出来,只能用笨方法,方法如下:
Type:vUnsignedInt An argument that specifies the first operand of the calculation. Name:Arg2 Type:vUnsignedInt An argument that specifies the second operand of the calculation. Return Value: Type:PtgUnsWord This function returns a PtgUnsWord containing the value of the bitwise XOR operation betwe...
staticintgetOpFromAssignmentOp(Node n){switch(n.getType()){caseToken.ASSIGN_BITOR:returnToken.BITOR;caseToken.ASSIGN_BITXOR:returnToken.BITXOR;caseToken.ASSIGN_BITAND:returnToken.BITAND;caseToken.ASSIGN_LSH:returnToken.LSH;caseToken.ASSIGN_RSH:returnToken.RSH;caseToken.ASSIGN_URSH:returnToken.URSH;c...
Facebookx.comLinkedInE-mail Stampa 2.5.4.12 BitXor Articolo 15/02/2019 TheBitXorfunction performs the bitwise XOR operation. ABNF: BitXor = val val " BITXOR():128" Required Arguments: Name:Arg1 Type:vUnsignedInt An argument that specifies the first operand of the calculation. ...