}/*** NLR:前序遍历(Preorder Traversal 亦称(先序遍历)) * 访问根结点的操作发生在遍历其左右子树之前。*/publicvoidpreOrderTraversal() {//NSystem.out.print(this);//Lif(this.leftSubNode !=null) {this.leftSubNode.preOrderTraversal(); }//Rif(this.rightSubNode !=null) {this.rightSubNode.p...
Given a binary tree, return thepostordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[3,2,1]. 1classSolution {2public:3vector<int> postorderTraversal(TreeNode *root) {4vector<int>result;5stack<TreeNode *>s;6TreeNode *p =root;7Tree...
Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level). Example 1: Input: root = [3,9,20,null,null,15,7] Output: [[3],[9,20],[15,7]] Example 2: Input: root = [1] Output: [[1]] Example ...
Algorithm postorder(t) /*t is a binary tree .Each node of t has three fields: lchild, data, and rchild.*/ { If t! =0 then { Postorder(t->lchild); Postorder(t->rchild); Visit(t); } } Example: Let us consider a given binary tree.Therefore the postorder traversal of the above ...
此题来自leetcode https://oj.leetcode.com/problems/binary-tree-postorder-traversal/ Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 代码语言:javascript 复制 1\2/3
二叉树的中序遍历。 解法一 递归 学二叉树的时候,必学的算法。用递归写简洁明了,就不多说了。 publicList<Integer>inorderTraversal(TreeNoderoot){List<Integer>ans=newArrayList<>();getAns(root,ans);returnans;}privatevoidgetAns(TreeNodenode,List<Integer>ans){if(node==null){return;}getAns(node.lef...
Traversing a binary tree refers to visiting and processing each node in the tree in a specific order. There are three common methods for traversing binary trees: Inorder Traversal: In an inorder traversal, the nodes are visited in the order: left subtree, current node, right subtree. This ...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
AI检测代码解析 # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]: ...
An example for level-order Traversal + * E D C / B A Level-order traversal: + * E * D / C A B 二元樹的Level-order traversal void level_order (tree_pointer ptr) { /* level order tree traversal */ int front = near = 0; tree_pointer queue [MAX_QUEUE_SIZE]; if (!ptr) retu...