Given a binary tree, return thepostordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[3,2,1]. 1classSolution {2public:3vector<int> postorderTraversal(TreeNode *root) {4vector<int>result;5stack<TreeNode *>s;6TreeNode *p =root;7Tree...
https://oj.leetcode.com/problems/binary-tree-level-order-traversal-ii/ Given a binary tree, return thebottom-up level ordertraversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20...
1 struct TreeNode { 2 int val; 3 TreeNode* left; 4 TreeNode* right; 5 TreeNode(int x): val(x), left(NULL),right(NULL) {} 6 }; 7 8 void Swap(vector<int> &ivec) 9 { 10 int temp = 0; 11 int len = ivec.size(); 12 for (int i = 0; i < len/2; i ++) { 13...
Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level). Example 1: Input: root = [3,9,20,null,null,15,7] Output: [[3],[9,20],[15,7]] Example 2: Input: root = [1] Output: [[1]] Example ...
Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is in the range [0, 100]. -100 <= Node.val <= 100 英文版地址 leetcode.com/problems/b 中文版描述 给定一个二叉树的根节点 root ,返回 它的中序 遍历。 示例1: 输入:root = [1,null,2,3] ...
Traversing a binary tree refers to visiting and processing each node in the tree in a specific order. There are three common methods for traversing binary trees: Inorder Traversal: In an inorder traversal, the nodes are visited in the order: left subtree, current node, right subtree. This ...
/*t is a binary tree .Each node of t has three fields: lchild, data, and rchild.*/ { If t! =0 then { Postorder(t->lchild); Postorder(t->rchild); Visit(t); } } Example:Let us consider a given binary tree. Therefore the postorder traversal of the above tree will be:0,2,4...
Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree [3,9,20,null,null,15,7], 3/\920/\157 1.
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
An example for level-order Traversal + * E D C / B A Level-order traversal: + * E * D / C A B 二元樹的Level-order traversal void level_order (tree_pointer ptr) { /* level order tree traversal */ int front = near = 0; tree_pointer queue [MAX_QUEUE_SIZE]; if (!ptr) retu...