1privateList<String> res;//stores the final output23publicList<String>binaryTreePaths(TreeNode root) {4this.res =newArrayList<>();5helper(root, "");6returnthis.res;7}89//helper function that does basic depth first traversal10privatevoidhelper(TreeNode root, String str) {11if(root ==null...
When dealing with binary tree related problem, traversals using recursion is our friend. It seems we can perform a post-order traversal, and keep track of the maximum sums. If the path has to go through root, then in each post-order step, we will have the max_sum_of_the_left_path, ...
left, path); dfs(root.right, path); } } Python 代码 栈 + 循环实现 # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def binaryTreePaths(sel...
3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 vector<string> ans; 12 public: 13 void DFS(string path,TreeNode* t) 14 { 15 if(t->left=...
leetcode 543. Diameter of Binary Tree 最长树的片段 + 深度优先遍历DFS,Givenabinarytree,youneedtocomputeenanytwonodesinatree.Thispathmayormayn...
问题链接 英文网站:199. Binary Tree Right Side View中文网站:199. 二叉树的右视图问题描述Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the n…
简单 95. 不同的二叉搜索树 II 74.6% 中等 96. 不同的二叉搜索树 71.5% 中等 98. 验证二叉搜索树 39.3% 中等 99. 恢复二叉搜索树 61.3% 中等 100. 相同的树 63.2% 简单 101. 对称二叉树 62.3% 简单 102. 二叉树的层序遍历 69.7% 中等 103. 二叉树的锯齿形层序遍历 60.2% 中等 104. 二叉树的最大...
145. 二叉树的后序遍历 - 给你一棵二叉树的根节点 root ,返回其节点值的 后序遍历 。 示例 1: 输入:root = [1,null,2,3] 输出:[3,2,1] 解释: [https://assets.leetcode.com/uploads/2024/08/29/screenshot-2024-08-29-202743.png] 示例 2: 输入:root =
http://bangbingsyb.blogspot.com/2014/11/leetcode-binary-tree-maximum-path-sum.html http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。
二维树状数组Binary Indexed Tree LeetCode题目:308. Range Sum Query 2D - Mutable Given a 2D matrixmatrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1,col1) and lower right corner (row2,col2). ...