publicclassval;TreeNodeleft;TreeNoderight= 基本概念 "二叉树"(Binary Tree)这个名称的由来是因为二叉树的每个节点最多有两个子节点,一个左子节点和一个右子节点。其中,“二叉”指的是两个,因此“二叉树”表示每个节点最多可以分支成两个子节点。基本定义: 每个节点包含一个值(或数据),另外最多有两个子节点。
1template<classT>2classBinaryTreeNode3{4friendclassBinaryTree<T>;5private:6T element;//结点的数据域7BinaryTreeNode<T>* LeftChild;//结点的左孩子结点8BinaryTreeNode<T>* RightChild;//结点的右孩子结点9public:10BinaryTreeNode();11BinaryTreeNode(constT&ele);12BinaryTreeNode(constT& ele, Binary...
}//二叉树反转intreversal(std::shared_ptr<Node>pTreeNodeStart) {if(pTreeNodeStart ==nullptr)return0;//reversal left treereversal(pTreeNodeStart->m_pLeftChild);//reversal right treereversal(pTreeNodeStart->m_pRightChild);//swap left child and right childstd::swap(pTreeNodeStart->m_pLeft...
1. Maximum Depth of Binary Tree 解法1: class Solution: def maxDepth(self, root: TreeNode) -> int: self.answer = 0 self.helper(root,0) return self.answer def helper(self,node,depth): if node is None: self.answer=max(self.answer,depth) else: self.helper(node.left,depth+1) self....
classSolution:defmaxDepth(self,root:TreeNode)->int:ifnotroot:return0return1+max(self.maxDepth(root.left),self.maxDepth(root.right)) 2 /平衡二叉树\color{green}{(Easy)} -- 问题描述 给定一个二叉树,判断它是否是高度平衡的二叉树。 一棵高度平衡二叉树定义为:一个二叉树每个节点的左右两个子树的...
class Node: def __init__(self, data): self.data = data self.lchild = None self.rchild = None 1. 2. 3. 4. 5. 2. 查找与插入 当二叉查找树不为空时: 首先将给定值与根结点的关键字比较,若相等,则查找成功 若小于根结点的关键字值,递归查左子树 ...
pip install binarytree 在binarytree库中,可以供我们导入使用的有1个类和5个函数。下面会依次介绍每一个类或函数的用法。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 __all__=['Node','tree','bst','heap','build','get_parent']
To provide a binary tree-specific node class, we can extend the base Node class by creating a BinaryTreeNode class that exposes two properties—Left and Right—that operate on the base class's Neighbors property.public class BinaryTreeNode<T> : Node<T> { public BinaryTreeNode() : base()...
Design a binary tree node class with the following methods:is_locked, which returns whether the node is locked lock, which attempts to lock the node. If it cannot be locked, then it should return false. Otherwise, it should lock it and return true. unlock, which unlocks the node. If ...
a binary tree's nodes have at most two children, commonly referred to as left and right. To provide a binary tree-specific node class, we can extend the base Node class by creating aBinaryTreeNodeclass that exposes two properties—LeftandRight—that operate on the base class'sNeighborsproper...