Given the below binary tree, 1 / \ 2 3 Return 6. 2.解法分析: leetcode中给出的函数头为:int maxPathSum(TreeNode *root) 给定的数据结构为: Definitionforbinary tree *structTreeNode { *intval; * TreeNode *left; * TreeNode *right; * TreeNode(intx) : val(x), left(NULL), right(NULL...
}//对每个节点遍历求左右两个节点的做大加上本身,然后取最大的值就是maximum path sum了intmaxPathSum(TreeNode *root) {if(!root)return0;inttmpl = INT_MIN, tmpr =INT_MIN;intcur =curMax(root);if(root ->left) tmpl= maxPathSum(root ->left);if(root ->right) tmpr= maxPathSum(root ->...
Given a non-empty binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root...
取其4个值中得最大值作为子树的最大路径和。 classSolution {public:intmaxSum =INT_MIN;intgetMaxSum(TreeNode*root){if(root == NULL)return0;intleftSum = getMaxSum(root->left), rightSum = getMaxSum(root->right);intcurSum = max(root->val, max(root->val+leftSum, root->val+rightSum...
Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example: Given the below binary tree, AI检测代码解析 1 / \ 2 3 1. 2. 3. Return6. 题意: 给定一棵二叉树,找出最大得路径和。
52. N 皇后 II N-Queens II 力扣 LeetCode 题解 07:06 53. 最大子数组和 Maximum Subarray 力扣 LeetCode 题解 03:58 54. 螺旋矩阵 Spiral Matrix 力扣 LeetCode 题解 05:59 55. 跳跃游戏 Jump Game 力扣 LeetCode 题解 03:23 56. 合并区间 Merge Intervals 力扣 LeetCode 题解 04:17 57...
Binary Tree Maximum Path Sum 83 -- 5:41 App Leetcode-0111. Minimum Depth of Binary Tree 76 -- 1:11 App Leetcode-0104. Maximum Depth of Binary Tree 8 -- 5:41 App Leetcode-0110. Balanced Binary Tree 23 -- 6:11 App Leetcode-0114. Flatten Binary Tree to Linked List 89 ...
http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。 ** 总结: pre-order -> top-down post-order -> bottom-up in-order -> ? level-order -> bfs ...
Given a non-empty binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root...
Binary Tree Maximum Path Sum@LeetCode Binary Tree Maximum Path Sum 动态规划+深度优先搜索。把大问题(求整棵树的路径最大值)拆分成小问题(每颗子树的路径最大值),递推公式为:当前树的路径最大值=max(左子树的路径最大值, 右子树的路径最大值)+当前根节点的值。以此来推出最后全树的最大路径值。