intBinarySearchTemplate(vector<int>& v,intcond){intlow=0, high=somehighvalue,ans=choose value according to question;while(high>=low) {intmid=(low+high)/2;if(findisBoundary(mid, h,cond)) { Twocase//1. shrink high=mid-1 or mid+1 and calucate answer//2. shring low=mid+1 or mid+...
{"id":"8","name":"字符串转换整数 (atoi)","url":"https://leetcode-cn.com/problems/string-to-integer-atoi","solutionNum":"2131","solutionUrl":"https://leetcode-cn.com/problems/string-to-integer-atoi/solution","percentOfPass":"21.4%","levelMedium":"中等","context":null,"folderNam...
Subscribeto see which companies asked this question 没看明白什么意思。以为是给一个数组{1,#,2,3}作为输入,需要先重建二叉树,然后进行中序遍历,结果给的接口是以TreeNode*为参数;以为是以'#'代替空节点作为终止标识的,结果判断叶子节点还是以NULL为标记。不知前面给这么多example和OJ's Binary Tree Serializat...
After a lot of practice in LeetCode, I've made a powerful binary search template and solved many Hard problems by just slightly twisting this template. I'll share the template with you guys in this post.I don't want to just show off the code and leave. Most importantly, I want to s...