TreeNode(intx) : val(x), left(NULL), right(NULL) {} };classSolution {public: TreeNode*sortedArrayToBST(vector<int> &num) {if(num.empty())returnNULL; TreeNode*root=NULL;inti;for(i=0; i<(int)num.size(); i++) insert(root,num[i]);returnroot; }voidinsert(TreeNode *&root,int...
TreeNode(intx) : val(x), left(NULL), right(NULL) {} }; TreeNode *CreateBinaryTreeNode(intvalue); voidConnectTreeNodes(TreeNode *pParent, TreeNode *pLeft, TreeNode *pRight); voidPrintTreeNode(TreeNode *pNode); voidPrintTree(TreeNode *pRoot); voidDestroyTree(TreeNode *pRoot); #endif/...
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. Example: AI检测代码解析 Given th...
Can you solve this real interview question? Convert Sorted Array to Binary Search Tree - Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree. Example 1: [https://assets.lee
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 数组的中点肯定就是平衡BST的根节点,以此规律递归。 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; ...
data in a non-linear fashion. After discussing the properties of binary trees, we'll look at a more specific type of binary tree—the binary search tree, or BST. A BST imposes certain rules on how the items of the tree are arranged. These rules provide BSTs with a sub-linear search ...
data in a non-linear fashion. After discussing the properties of binary trees, we'll look at a more specific type of binary tree—the binary search tree, or BST. A BST imposes certain rules on how the items of the tree are arranged. These rules provide BSTs with a sub-linear search ...
二叉搜索树(Binary Search Tree,简称BST)也称为二叉查找树、有序二叉树(Ordered Binary Tree),或排序二叉树(Sorted Binary Tree)。二叉搜索树是一颗空树,或具有以下性质的二叉树: 如果任意节点的左子树不为空,则左子树上所有节点的值小于它的根节点的值。
public: TreeNode *sortedArrayToBST(vector<int> &num) { return create(num,0,num.size()-1); } TreeNode* create(vector<int>num,int L,int R) { if(L>R)return NULL; int mid=(R+L+1)/2; //BST树总是从左到右排满的,如果不优先选右边的这个,{1,3}结果为{1,#,3},而实际结果应为...
publicTreeNodesortedArrayToBST(int[]nums){returnsortedArrayToBST(nums,0,nums.length);}privateTreeNodesortedArrayToBST(int[]nums,intstart,intend){if(start==end){returnnull;}intmid=(start+end)>>>1;TreeNoderoot=newTreeNode(nums[mid]);root.left=sortedArrayToBST(nums,start,mid);root.right=so...