Given a binary search tree, print the elements in-order iteratively without using recursion.Note:Before you attempt this problem, you might want to try coding a pre-order traversal iterative solution first, because it is easier. On the other hand, coding a post-order iterative version is a ...
这个遍历方式也是LeetCode中 Binary Tree Inorder Traversal 一题的解法之一。 附题目,Binary Tree Inorder Traversal Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note:Recursive solution is trivial,...
TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) { //step1:construct hash-tab if(preorder.size()==0) return NULL; unordered_map<int,int> mapIndex; for(int i=0;i<inorder.size();i++) mapIndex[inorder[i]] = i; return helpTree(preorder,0,inorder.size(),0,m...
Inorder traversal Postorder traversal Essentially, all three traversals work in roughly the same manner. They start at the root and visit that node and its children. The difference among these three traversal methods is the order with which they visit the node itself versus visiting its children....
Inorder traversal Postorder traversal Essentially, all three traversals work in roughly the same manner. They start at the root and visit that node and its children. The difference among these three traversal methods is the order with which they visit the node itself versus visiting its children....
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line. ...
解析 这个题和上一个题目几乎一致,中序遍历不变,只是根节点的寻找从前序变为后序。 伪代码 node=post[n]k=findnode(in,node)node.left=f(in[:k],post[:k])node.right=f(in[k+1:],post[k:n])returnnode 代码 funcbuildTree(inorder[]int,postorder[]int)*TreeNode{l:=len(postorder)ifl==0{ret...
Binary Tree Level Order Traversal 二叉树层序遍历 Example Givenbinary tree[3,9,20,null,null,15,7],3/\920/\157returnits level order traversalas:[[3],[9,20],[15,7]] BFS方法 var levelOrder=function(root){if(!root)return[]conststack=[root]constres=[]while(stack.length){constlen=stack...
Construct Binary Tree from Inorder and Postorder Traversal ——通过中序、后序遍历得到二叉树 题意:根据二叉树的中序遍历和后序遍历恢复二叉树。 解题思路:看到树首先想到要用递归来解题。以这道题为例:如果一颗二叉树为{1,2,3,4,5,6,7},则中序遍历为{4,2,5,1,6,3,7},后序遍历为{4,5,2,6,...
1TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) {2//Start typing your C/C++ solution below3//DO NOT write int main() function4TreeNode *root =newTreeNode(0);5if(inorder.size() ==0){6returnNULL;7}8vector<int>leftInorder, leftPostorder, rightInorder, rightPostor...