二进制搜索将可搜索项目减半,从而减少了对更少数字进行比较的次数。 伪代码 (Pseudocode) 二进制搜索算法的伪代码应如下所示 - Procedure binary_search A← sorted array n← size of array x← value to be searched Set lowerBound = 1 Set upperBound = n while x not found if upperBound < lowerBound...
用pseudocode的形式的话,就是这样: 1 2 3 4 5 6 7 8 9 PREORDER-WALK(x) 1if(x!=NIL) 2 PREORDER-WALK(x.left) 3 print x.key 4 PREORDER-WALK(x.right) 3. BST的几种基本操作: SEARCH, MINIMUM, MAXIMUM, PREDECESSOR, SUCCESSOR, INSERT, and DELETE. 2.1 SEARCH: 1 2 3 4 5 6 7 8...
parameters, steps along with proper illustrations. The article explained in detail both the ways binary search can be implemented and showed them with pseudocode. It also explained the real-world scenarios and explained with proper examples. It can be understood more in detail by practicing ...
And we might write the pseudocode as: algorithm LEFT_ROTATE(node): // INPUT // node = the node to rotate around // OUTPUT // the tree after performing a left rotation on the given node x <- node.right node.right <- x.left x.left <- node x.color <- node.color node.color <-...
The pseudocode of binary search algorithms should look like this −Procedure binary_search A ← sorted array n ← size of array x ← value to be searched Set lowerBound = 1 Set upperBound = n while x not found if upperBound < lowerBound EXIT: x does not exists. set midPoint = ...
Return the root of the updated binary search tree. Here is the pseudocode for deletion in a binary search tree: function deleteNode(root, value): if root is NULL: return root if value < root->data: root->left = deleteNode(root->left, value) else if value > root->data: root->right...
but in reality he didn't know about the binary search algorithm until recently. After reading some literature Andrey understood that this algorithm allows to quickly find a certain number x in an array. For an array a indexed from zero, and an integer x the pseudocode of the algorithm is ...
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It turns out that we can fix this problem using only 2 queries. How? The pseudocode below explains; ANALYSIS OF THE SECOND APPROACH We have successfully eliminated the use of 2 queries at every step of the BS. However, we also introduced extra 2 queries to determine w...
Pseudocode ## 递归 BinarySearch(A,low,high,key): if high<low: return low-1 mid = low + (high-low)/2 #如果(high-low)/2不为整数,向下取整 if key == A[mid]: return mid if key<A[mid]: return BinarySearch(A,low,mid-1,key) if key>A[mid]: return BinarySearch(A,mid+1,high,key...