Problem 1: Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,...
The simplest solution would be to check every element one by one and compare it with k (a so-called linear search). This approach works in O(n) , but doesn't utilize the fact that the array is sorted.Binary search of the value 7 in an array. The...
cur->right =sortedArrayToBST(right);returncur; } }; 类似题目: Convert Sorted List to Binary Search Tree 参考资料: https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/discuss/35220/My-Accepted-Java...
intstart,intend){if(start==end){returnnull;}intmid=(start+end)>>>1;TreeNoderoot=newTreeNode(nums[mid]);root.left=sortedArrayToBST(nums,start,mid);root.right=sortedArrayToBST(nums,mid+1,end);returnroot;}
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: Given the sorted arr...
题目链接:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 新建一个结点保存mid值,该结点的左右子树也递归生成,这是个常用的模板 ...
108. Convert Sorted Array to Binary Search Tree 描述 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never diff...
解析 高度平衡,保险起见,左右节点个数相同且均衡分配即可。二叉树问题还是递归问题,将数组分割成左右两个部分,然后递归求解即可。 伪代码 root=mid(nums)root.left=f(nums[:half])root.Right=f(nums[half+1:]) 代码 funcsortedArrayToBST(nums[]int)*TreeNode{iflen(nums)==0{returnnil}k:=len(nums)/2...
108. Convert Sorted Array to Binary Search Tree 思路:从数组中间拿根,然后进行中根遍历; 练习指数:5
The array may contain duplicates. KEY WORDS: [Rotated sorted array] [find target] [contain duplicates] publicbooleansearch(int[] nums,inttarget) {if(nums ==null|| nums.length == 0)returnfalse;intleft = 0;intright = nums.length - 1;while(left <=right) {intmid = left + (right - ...