[LeetCode] 278. First Bad Version_Easy tag: Binary Searchfirst index, without duplicates [LeetCode] 162. Find Peak Element(852. Peak Index in a Mountain Array)_Medium tag: Binary Search [LeetCode] 74. Search a 2D Matrix_Medium tag: Binary Search [LeetCode] 240. Search a 2D Matrix II...
Similar Questions Search in a Sorted Array of Unknown Size Medium Maximum Count of Positive Integer and Negative Integer Easy Discussion (152) Copyright ©️ 2025 LeetCode All rights reserved 12.5K 152 0 Online nums = [-1,0,3,5,9,12] ...
6、api 这里讨论了一种方法,可以看一下:https://discuss.leetcode.com/topic/4659/c-in-order-traversal-and-please-do-not-rely-on-buggy-int_max-int_min-solutions-any-more
Input:root = [4,2,7,1,3], val = 5Output:[] Constraints: The number of nodes in the tree is in the range[1, 5000]. 1 <= Node.val <= 107 rootis a binary search tree. 1 <= val <= 107 FindTabBarSize FindBorderBarSize
LeetCode Top 100 Liked Questions 96. Unique Binary Search Trees (Java版; Medium) 题目描述 Given n, how many structurally unique BST's (binary search trees) that store values 1 ...n? Example: Input: 3 Output: 5 Explanation: Given n = 3, there are a total of 5 unique BST's: ...
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LeetCode Top 100 Liked Questions 236. Lowest Common Ancestor of a Binary Tree (Java版; Medium) 题目描述 Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined betw...
来自专栏 · LeetCode刷题记录 98. Validate Binary Search Tree 难度:medium Given a binary tree, determine if it is a valid binary search tree (BST).Assume a BST is defined as follows:The left subtree of a node contains only nodes with keys less than the node's key.The right subtree ...
Demonstrate all the questions on LeetCode in the form of animation.(用动画的形式呈现解LeetCode题目的思路) Resources Readme Activity Stars 0 stars Watchers 0 watching Forks 0 forks Report repository Releases No releases published Packages No packages published Languages Java 99.5% Other...
Code implementation of the second approach in Java CONCLUSION I would also like to add that if the max element in the array is not unique (i.e. if the array contains non-distinct values), the above approach would still return the index of one of the max elements.If y...