Can you solve this real interview question? Binary Search Tree Iterator - Implement the BSTIterator class that represents an iterator over the in-order traversal [https://en.wikipedia.org/wiki/Tree_traversal#In-order_(LNR)] of a binary search tree (BST):
Description:Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.Calling next() will r
=null){nodeStack.Push(node);node=node.left;}}publicBSTIterator(TreeNode root){nodeStack=newStack<TreeNode>();PushLeft(root);}/** @return whether we have a next smallest number */publicboolHasNext(){returnnodeStack.Count>0?true:false;}/** @return the next smallest number...
题目地址: https://leetcode.com/problems/binary-search-tree-iterator/ 题目内容: Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Callingnext()will return the next smallest number in the BST. Note:next()andhasNext()should...
Left } } /** * Your BSTIterator object will be instantiated and called as such: * obj := Constructor(root); * param_1 := obj.Next(); * param_2 := obj.HasNext(); */ 题目链接: Binary Search Tree Iterator : leetcode.com/problems/b 二叉搜索树迭代器: leetcode-cn.com/problem ...
BSTIterator(TreeNode root)Initializes an object of theBSTIteratorclass. Therootof the BST is given as part of the constructor. The pointer should be initialized to a non-existent number smaller than any element in the BST. boolean hasNext()Returnstrueif there exists a number in the traversal...
Leet Code 第173题Binary Search Tree Iterator 解题思路 Loading...1、读题,题目要求为BST 实现一个迭代器,有二个方法,next 和hasNext 方法。 2、先按照中序遍历,变成一个数组或list等,再按照索引取值。 3、…
https://leetcode.com/problems/binary-search-tree-iterator/ 本人比较菜,一般看到这个就只想到,这个题目要求从小到大遍历一个二叉搜索树 ,当然就是中序遍历了。但是始终搞不明白题目的要求 next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the...
https://leetcode.com/problems/binary-search-tree-iterator/ 题目描述 Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. ...
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